prob_019 (2) - v 1 = 2 r 1 / T and v 2 = 2 r 2 / T ....

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19. REASONING AND SOLUTION If F is the net force on mass 2, then 2 F is the net force on mass 1, and we have For mass 1: 2 F = m 1 v 1 2 / r 1 For mass 2: F = m 2 v 2 2 / r 2 Dividing the equations and rearranging gives m 2 / m 1 = (1/2)( r 2 / r 1 )( v 1 / v 2 ) 2 = ( v 1 / v 2 ) 2 since r 2 = 2 r 1 The period of revolution is the same for both masses so
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Unformatted text preview: v 1 = 2 r 1 / T and v 2 = 2 r 2 / T . Dividing these gives v 1 / v 2 = r 1 / r 2 = 1/2. Now m 2 / m 1 = (1/2) 2 = 1 4 _______________________________________________________________________________________ ______...
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This note was uploaded on 01/29/2010 for the course CALC 01:640:135 taught by Professor Soffer during the Spring '08 term at Rutgers.

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