prob_076

# prob_076 - T = ma x + μ k mg cos 30.0° + mg sin 30.0° T...

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76. REASONING AND SOLUTION If the + x axis is taken to be parallel to and up the ramp, then Σ F x = ma x gives T f k mg sin 30.0° = ma x where f k = μ k F N . Hence, T = ma x + μ k F N + mg sin 30.0° (1) Also, Σ F y = ma y gives F N mg cos 30.0 ° = 0 since no acceleration occurs in this direction. Then F N = mg cos 30.0 ° (2) Substitution of Equation (2) into Equation (1) yields
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Unformatted text preview: T = ma x + μ k mg cos 30.0° + mg sin 30.0° T = (205 kg)(0.800 m/s 2 ) + (0.900)(205 kg)(9.80 m/s 2 )cos 30.0° + (205 kg)(9.80 m/s 2 )sin 30.0° = 2730 N ______________________________________________________________________________________ ______...
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## This note was uploaded on 01/29/2010 for the course CALC 01:640:135 taught by Professor Soffer during the Spring '08 term at Rutgers.

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