171_ProbSet_3_key_2008

171_ProbSet_3_key_2008 - CHEM171-— Solutions to Homework...

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Unformatted text preview: CHEM171 --— Solutions to Homework 3 1. a. A point (center of inversion), axis (rotation), or a plane (mirror plane) about which a symmetry operation is performed. b. An action, which if performed, leaves the object/molecule apparently unchanged. c. A classification dependent on the symmetry an object possesses. 2. ONCI only possesses a plane of symmetry (the plane N=0: that contains all three atoms). :.Cl./ 3 .. m , '7‘ JMHHB ' k 3- ho“... [fa-3- . / - ”wrong... it Q” ‘ :‘I .9" -‘I «bugs; __ _ nua- 4"... 1pm}. H h H “-41%”. Sr c- 80 ‘k‘ I «HI-ti. /sn\ 1:. “11.4 ' 51;, F“- 6r EL ." J on?!“ f F ' i 1’ a" Hat. 9.5. “”7 “I" O“ 3-0.. F L F e' ASP, k:‘c' ‘ SmuLL’ FiAg-n—F ”(2.5 ' . . F l . . W P 9-. f X431 Yol le’ 0' 4013““ .m’ ‘ L 3"...4 ' S Ta .7. r"- o’g o m ...M__...H mm...“ W , ”a, TV“ ““315... ' : T ‘ 4 w... s-p-u- O f‘a. 0w 3.5.0 CL I ‘ ?‘I «‘0 tin-154m?” /16\ “MP 8 - C, . " I a Re. 1349-“- UL M’ Cu Qfi 0.: ?¢’ F swag; s , .- 1.. ”0’... FAA ""' ' s: or i. amt-«“0: . /S\ .m... 0 . 0 but on F - w w l . “.4? his: ac’ __x‘:;' lo e’... SP4. I .. . ---~»~ .. m ' i F A's-4‘JACJ ’l .’ G' . e h. : w ”I; F a y%/ go 0.. 5w Git-Fungi; .H F —- c—r 1/3”“: C.” spud-r) neg. WWI?” ,4 l 9.: J: F am» 0. A F \ - .. 0' 96")“3’“. HW‘ . .\ .. /? “whack; (\X4 ,f 91(owut / ' . . <' l * CW swehf 4. fell" {pi- o/g \0 cu ".4 Ct: 1" 0‘, . 1' F 321.1313.’ . 9 “'9 1‘. F “Oi-fin“ o ‘F' WWW. ‘u-i= Cu 0”] a“) gay-ho a) Cay, b) Dosh and C) De}. Point group with highest symmetry = Ih, lowest = 61 C2 1,3-dimethylallene = C2 Cubane = 0.. Td point group has 6 ad planes and all pass through the central atom of the molecule but each ad plane only passes through two corner atoms (vertices). These six ad planes cut through the following corner atoms: DA, DB, DC, AB, BC, AC. Every time we reflect the molecule through a ad plane the tetrahedron gets bisected and the other two atoms, the ones that were not cut by the ad plane, become mirror images of each other. Eclipsed Conformation: Point Group Ca, = has reflection symmetry = $1 = Not Chiral. Staggered Conformation: Point Group Cal. = has reflection symmetry = $1 = Not Chiral. Gauche Conformations: Point Group C2 = no 5 symmetry, Chiral. Since at least one conformation contains 5 symmetry, and there is a free rotation about the different conformations, this molecule is Not Chiral. Interesting note: C2 symmetry cannot be lost by changing the conformation of the molecule. The ls orbital penetrates the atomic core the most out of all atomic orbitals and its proximity to the nucleus results in an exceedingly strong Coulombic interaction between the positively charged nucleus and the Is electron. Given that there are no other electrons between the Is electron and the nucleus, it does a poor job at screening. Also, electrons in the same orbital screen each other poorly. Helium BONUS: fir fir fir cork-'44.: leW-vrh par-5%:lpdn-r we... club-$1.: adg‘bpqu- .9 D“... W Dos. ...
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