# is3_101 - (343 hours after detonation there are 3...

This preview shows page 1. Sign up to view the full content.

Radiological Emergency Management Independent Study Course 4-14 Example Problem 1 If the exposure rate 1 hour after detonation is 1,000 R/hr, what will the exposure rate be 343 hours after detonation? There are three steps involved in solving this kind of problem. The first step is to determine the number of seven-fold increases in time after detonation between when the initial measurement was obtained and the future time of interest. The second step is to determine the expected magnitude of decrease during the time period of interest. The third step is to calculate the predicted exposure rate. O Step 1: Between the initial measurement (taken 1 hour after detonation) and the future time of interest
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: (343 hours after detonation), there are 3 seven-fold increases in time after detonation: (1 hour) (7)(7)(7) = 343 hours O Step 2: During three seven-fold increases in time, the magnitude of decrease in exposure rates is 1,000-fold. One thousand was calculated by multiplying 10 by itself three times: (10)(10)(10) = 1,000 O Step 3: The predicted exposure rate is 1 R/hr, which is 1,000 times less than the initial measurement of 1,000 R/hr. The solution for this step was performed as follows: Predicted exposure rate = Initial measurement Magnitude of decrease = 1 R/hr For this example, the solution for this step looks as follows: Predicted exposure rate = 1,000 R/hr 1,000 = 1 R/hr...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online