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Unformatted text preview: 3 COOH 1.8e-5 HClO 2 1.2e-2 HCl Very Large pKs Just as the [H + ] concentration can be a small number that is difficult to deal with, so can K a /K b values. Hence, we introduce the concept of the pK: pK a = -log(K a ) and pK b = -log(K b ) Rule: 14 = pK a + pK b for any conjugate acid/base pair at 25 o C. Example: Given the following K a values, compute the pK a of the acid and the K b and pK b of the conjugate bases: K a : 1e-10 1e-3 1 1000 1e10 pK a : K b : pK b : Note that as acid strength increases, the pK a will decrease. As base strength increases, the pK b will decrease. Example:...
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- Fall '07
- kA, pKb, conjugate acid/base pair