Exam 2 - Version 084 Exam 2 Lyon (52380) 1 This print-out...

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Unformatted text preview: Version 084 Exam 2 Lyon (52380) 1 This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. PLEASE BE SURE TO BUBBLE YOUR NAME, EID AND EXAM VERSION NUM- BER ON YOUR ANSWER SHEET BE- FORE IT IS SUBMITTED. 001 (part 1 of 4) 10.0 points Draw the Lewis structure for the following hydrocarbon molecule. The carbons are num- bered one to four starting with the far left carbon as one. CH 2 CCHCH 3 What is the molecular shape of carbon 4? 1. trigonal planar 2. tetrahedral correct 3. trigonal pyramidal 4. angular 5. bipyramidal 6. linear 7. square planar Explanation: The molecule has the structure C C C C Carbon 4 has bonds to one carbon and three hydrogens or RHED = 4. This is tetrahedral molecular geometry. 002 (part 2 of 4) 10.0 points What is the hybridization of carbon 2? 1. sp correct 2. sp 2 3. sp 4 4. sp 2 d 5. sp 3 6. sp 3 d 2 7. sp 3 d Explanation: The molecule has the structure C C C C Carbon 2 has bonds only to two other carbons (double bonds). This is RHED = 2 or sp hybridization. 003 (part 3 of 4) 10.0 points What are the bond angles of carbon 1? 1. less than 109.5 2. 109.5 3. 120 correct 4. 180 5. 90 , 120 , 180 6. 90 , 120 7. 90 , 180 Explanation: The molecule has the structure C C C C Carbon 1 has bonds to one carbon and two hydrogens or RHED = 3. This is trigonal planar molecular geometry with bond angles of 120 degrees. 004 (part 4 of 4) 10.0 points Carbon 3 has 1. 2 sigma bonds and 2 pi bonds. 2. no sigma bonds and 4 pi bonds. 3. 1 sigma bonds and 3 pi bonds. 4. 4 sigma bonds and no pi bonds. 5. 3 sigma bonds and 1 pi bond. correct 6. 2 sigma bonds and 1 pi bonds. Version 084 Exam 2 Lyon (52380) 2 Explanation: The molecule has the structure C C C C Carbon 3 has bonds to two other carbons (one double bond) and one hydrogen. Double bonds are composed of one sigma and one pi bond, therefore there is one sigma bond from the hydrogen, one sigma bond from the carbon, and one sigma with one pi from the double bond for a total of 3 sigma bonds and one pi bond. 005 10.0 points What is the hybridization at the atom indi- cated by the arrow in the following molecule? H H H H C O O H O C O C H H H Acetylsalicylic acid (Aspirin) 1. sp 2. sp 3 d 3. sp 3 d 2 4. sp 3 5. sp 2 correct Explanation: The C has RHED = 3 so three hybrid or- bitals are needed. The hybridization sp 2 pro- vides 3 orbitals. 006 10.0 points Write the electron-dot notation for the ele- ment P. 1. b P 2. None of these 3. b b b b b b b b P 4. b b P 5. b b b b b b P 6. b b b b b P correct 7....
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This note was uploaded on 01/30/2010 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas at Austin.

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Exam 2 - Version 084 Exam 2 Lyon (52380) 1 This print-out...

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