{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

BISC 330 Spring 2010 Lecture 3

# BISC 330 Spring 2010 Lecture 3 - BISC330L:Biochemistry...

This preview shows pages 1–5. Sign up to view the full content.

BISC 330L:  Biochemistry Spring Semester 2010 USC Lecture:  Friday, 15 January 2010 1. Review Wednesday’s material 1. Continue Chapter 1 material…  Discovery of DNA  The Genomic revolution

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Henderson-Hasselbalch  Equation For acid AH (proton donor in neutral form): AH              A -  + H +                         K a  = [A - ][H + ]/[AH]                     logK a  = log[H + ] + log([A - ]/[AH])   - log[H+] = -logK a  + log([A - ]/[AH])                          pH = pK a  + log([A - ]/[AH])             (Henderson-Hasselbalch  Equation)                         NOTE: [A - ]/[AH] = 10  pH-pKa   [A-] = [AH](10  pH-pKa ) [AH] = [A-]/(10  pH-pKa )                             Fraction ionized (f = f A -): f  = [A ]/([A ]+[AH]) = (10  )/(1 + 10  )
pH f i  = f A  = 10 pH-pKa /(1+10 pH-pKa ) -3+pKa 10 -3  / (1+10 -3 )   = 0.001 -2+pKa 10 -2  / (1+10 -2 )   = 0.01 -1+pKa 10 -1  / (1+10 -1 )   = 0.1 pKa 1   / (1+1)   = 0.5 1+pKa 10 / (1+10 1 )   = 0.9 2+pKa 10 / (1+10 2 )   = 0.99 3+pKa 10 / (1+10 3 )   = 0.999 Fraction ionized (f = f A -): f I  = [A - ]/([A - ]+[AH]) = (10  pH-pKa )/(1 + 10  pH- pKa )

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Graph of the data
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern