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Unformatted text preview: does not have tuberculosis? Solution. Applied Math and Statistics Quiz 2 AMS7. 2 P ( T +  ¯ D ) = 51 1790 = 0 . 0285 4. (10 points) What is the probability of a negative xray given that a subject does not have tuberculosis? Solution. P ( T ¯ D ) = 1739 1790 = 0 . 9715 5. (40 points) Assume that the probability that an individual in the general population has tuberculosis is 0.000093. What is the probability that a randomly selected individual has tuberculosis given that his or her xray is positive? (Hint: use Bayes’ rule). Solution. P ( D  T + ) = P ( T +  D ) P ( D ) P ( T +  D ) P ( D ) + P ( T +  ¯ D ) P ( ¯ D ) = . 733 × . 000093 . 733 × . 000093 + 0 . 0285 × . 999907 = 0 . 00239...
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 Winter '08
 Prado,R
 Statistics, Applied Mathematics, negative xray, positive xray

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