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Unformatted text preview: does not have tuberculosis? Solution. Applied Math and Statistics Quiz 2 AMS7. 2 P ( T +  D ) = 51 1790 = 0 . 0285 4. (10 points) What is the probability of a negative xray given that a subject does not have tuberculosis? Solution. P ( T D ) = 1739 1790 = 0 . 9715 5. (40 points) Assume that the probability that an individual in the general population has tuberculosis is 0.000093. What is the probability that a randomly selected individual has tuberculosis given that his or her xray is positive? (Hint: use Bayes rule). Solution. P ( D  T + ) = P ( T +  D ) P ( D ) P ( T +  D ) P ( D ) + P ( T +  D ) P ( D ) = . 733 . 000093 . 733 . 000093 + 0 . 0285 . 999907 = 0 . 00239...
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This note was uploaded on 01/31/2010 for the course AMS 7 taught by Professor Prado,r during the Winter '08 term at UCSC.
 Winter '08
 Prado,R
 Statistics, Applied Mathematics

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