physics midterm answer key 1

physics midterm answer key 1 - Name 1 A steel rod 0.350 m...

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Unformatted text preview: Name: 1. A steel rod 0.350 m long and an aluminum rod 0.250 m long, both with the same diameter, are placed end to end between rigid supports with no initial stress in the rods at —20 OC. The temperature of the rods is now raised to 40 °C'. The length of the combined rod remains the same because of the rigid supports, but the lengths of the individual rods do not. asteel = 1.2 x 10"5(°C)”1, aAl = 2.4 x 10-5(°C)—1, Ysteel = 20 x 1010 Pa, and YA] = 7 x 1010 Pa a) Find the length of each rod at 40 0C. E ~ \3 [All A L z: o) LbAT b) Find the stress in each rod at 40 00. fl ‘” iv Fer cacti 7‘66] She»), 3 'l‘ Y : Whigs“ AT ALH‘ALL: a ‘0 L : ' ~AL Y! [éEmA‘ATJ *4; «5:0. «LATJ Y ALI ~O(\L€‘AT :: «Y3 9L4 ‘aLYLA‘Y ‘ 1'. ’ L1 (Y‘ Q,” 4r? 133:1) : (calf- 0:1 (fiz> AT 1 L2 ’ Name: 2. (a) An engineer heats a 500 g unknown solid sample at the rate of 10.0 kJ / min starting at t = 0 While recording its temperature as a function of time. The data are plotted in the graph shown. (i) Determine the latent heat of fusion for this solid. (ii) Determine the specific heat of the solid state of the material. T(°C) (b) A copper pot with a mass of 0.500 kg contains 0.170 kg of water at a temperature of 20.000. A 0.250 kg block of iron at 85.000 is dropped into the pot. Determine the final ' temperature. Assume no heat is lost to the surroundings. 0011 = 385%, cwater = 41mg}? and 01:8 2 4501?K AC1: O MchcWh; ’10) +MMV Cami? (13:20} +MFQCFe(1;~ 8y) I; o (o. 53(SYSYM; “203 “Nov 1703CL\.\‘T0\ (711—10) *- (o.2:) (4375) (To! ~853=o 1] 1. 112°C Name: 3. An ideal monatomic gas with initial temperature 200 K at point a follows the cycle a —> b ——> c —+ a. ‘ a) What is the temperature at b? _ b) HOW much work is done for this cycle? 0) How much net heat is added or removed from the gas in the process b —> c? d) Specify if the heat is added or removed in part 0). Note: all curves are straight lines in the PV diagram below. P (in atm) m“ 2;“ R : pa Vb . To» To Pw 0. w— : m — * 3W h vc. 1': ‘ m 1 3 V (in I) Wg‘cte’ :: wobdb'l‘ wLflC—t dea Ck c) QB :- wh~>c+ Auk—9 c. wC ear-:0 becwe AV:O IQ” (A7“ —.) a h?" WG-1 c‘e 2 p“ ( Vb"V¢) (Vega) lg: mead W T 1;» Auto-5c, I W03“) Wbac I C i waft : (9138307; A --i ( E413 (Vc‘é we; 3 7?: wC‘jclo; .: {WV 907$“ TC: Pcvcrazgc, Ta 3M ,W—ZZMA Pa «3., a New Jug—k "0+ wont,“ dc ([9526! 4v’cwat’v (9 = (Zahle 32X \— {bafiqamm ma +2; b—éc Qb—IC‘J “Liale +li(“1‘“\)(-zm + 1‘ G—b—sc : —L$“Jmfl"’\0b“& *3}..ng AM a M t. (~13 M :- (—felg aw 521m: ...
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physics midterm answer key 1 - Name 1 A steel rod 0.350 m...

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