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lecture6 - =QOMROT3’C ®omMg9°> 3" E mm\oxac 3 MA=...

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Unformatted text preview: =QOMROT3’C +®omMg9°> 3" E mm? + \oxac, 3 MA= A; xF— mg; mg) EC??? «:72 +/0 9:63), x O ==QL3€A§3M+ afl‘waméxi —3CR?,1°7) GXL‘KMAE Mp. = acmsa éxJ -— ‘8H.6"7\§x5 _M#= umsak—bflswk O O 0 Determine the moment vector of the 50 lb force 1) about point A, 2) about point B. Express the moment in Cartesian vector form (in terms ofi ,j and k) 9in 9in 6in F = [4.334lb-(4.-i + 6,-j + 9.-k)] Raf: O-i _ 18-in-j + 12-in-k F = (17.3361b-i + 26.0041b j + 39.0061bk) i j k MA = Rafx F = 0 —18-i11 12-i11 17.336lb 26.004lb 39.006lb MA = (—1014.156i + 208.032j + 312.048k)-in-1b 9in F: 501b-£ 4-i+6-j+9~k f+§+¥ Raf: O-i—18-in-j+ 12.in-k ‘W o o o a. The moment of the force fibeut paint Q -‘-. A b The direction angles associated with many- F: ’75 O I; \ ‘ hm L -" Iliumi $179.! mi ‘ tor " ' " " ‘ (H) + [1. +Q_I3I ' ~ -_.. __ .' a c, 5— 7 =~K3|0 5L - 333. '73; — 5%. dumb K0. 2’: 1—395 -\— “EU/earn; Q A - ' "I *5/0 c-us..>~€9e Mo = ”:7“:- _ L30$+9410XC310 65—33975—599. r6562) =1an (:5 0 535m; *@6153R 83d”: KRPJCB 0 S‘BMZ—(a [1338 'DXM —<80'73(—,{73— —Q5‘ 4121 3):”: (Hm—(039,0, 51—7Hafiz’3 Q A M°= — mop-i 2 + comes $ —<3_o‘73«h w—ib \“MO\= ‘ QEOOD1 +® Flag-li—QG‘G)?‘ ,,: {3/300 IN'kh. ' C2,?! <330e: _ o = e 6W“ W) .5300 > = \‘SL? Q) 6(0-- (90,4)92 [2‘14 C =\-\\2fi.9 xiv“ ‘ng : \‘39'1.’ _\\N‘L~b V O A _ , L M} ‘1. C: Moments: , ‘ Moment of a force about a paint: / ii‘ k/ MOZrXF: 5x73; 7'27 13x11, 1-; f: (7’sz — rszfi + (1*sz — rxfz)j + (rxPy - rny)1< ‘ Moment of a, force abuut a line: Determine the scalar component of t e moment of the 100—1b force Qout the axis of the hinges (line AB). {\1 34 in. 0 Determine the scalar component of¢ne moment of the 100—1b foreegout the axis of the hinges (line AB). 33 w {232 + 2% 3 4— 5.6} c; . 6 Q L/ f‘ A "W My 34in.f ' Wig; ALE ? - 00%1 “I X ‘1" IVS" JE+§§I¢L 3&7 :c=57.5% L. -<,3 A73 4-5/- 77£ v A MB 5 (:8 C. XFQ 18 m . , ' _ ' ' 1%:- L34» + a '9. :51 X 1525‘, C” 63‘ 3m +¢ 1.3a] MM:-(§x_-L3 17);)“ +(Sl$l.79). 1.1/14 +Ea§£€7y$6U Ml £1315”? >5“: ,:>J Na. =-' 5’09 fist-MB—i—Hiiazefl 2.2 in y‘ "305 75'1“) V n 3739a.“ 8) L M a —]‘|,3‘i.:p2—HJH.3~'DQ 3375,7211”?- I”) *i ‘0‘ ‘ The magnitude of the force F is 595 N. Determine the scalar component of the moment at point 0 aboutlineOC.Z {/ffia 12.104'4—1903 +011 A A _ -' """" K/ n F .: 5?.ng "f'A'D;O~ t.t +aé +1019 ‘ I” 210 +200 ./ . luof‘loa =99; 3,7379 L1 + .0721 7R] VF “#770,134. goofing V L; . + 9 coma M0=LQQOI¥00vQIDCLxJQ . -1- 274(47704) ij' \ 91.. +69 5‘0’1‘1’ 0 £1.15) A x h .1. M75: ?)STOL/6‘(-3>-103£Wé:m 'A +9005? 4 m /M0=9405L—g840¥n (A)(N— p.) A 1/ 4x A “WW/714mm) 6“: ‘10" +°°+1°°hz jjj {1+ 6727/Q )n 197,3 ..- 7 96 O The magnitude of the force F is 5 95 N. Determine the scalar component of the moment at point 9 about line OC.. H .4. Q G 1 "2.10033? L Moog]: mp’«»é cc =EM.CL —— 9?. 04/3 +I0567AJ'L70-i- é7z71¢ =<9é. 05% 7mm +66 05X 071M 0 =64. 05' I: 73?) +Q§$ 671mm) “1/ 0 4-59 A force with a magnitude of 580 1b acts at a point in a body as shown in Fig. P4—59. Determine a. The moment of the force about point B. b. The direction angles associated with the moment vec- tor. .7:- fl; (5,, MomEWTO’F T: $548001“ ‘wwNB BA 7 «I O 0 4-87 A bracket is loaderd with sis-System of forces as shown in Fig. P4-87. Express the resultant of the force system in Cartesian vector form. . 49 A force with a magnitude of 650 lb acts at a point 0 in a body as shown in Fig. P449. Determine a. The moment of the force abeut poifit A. b. The directionangles associated with the moment vec- tor. ': 7 ‘ C. 13' ' Z F=6501b Fig. P449 ...
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