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lecture12 - -‘ Trusses Frames,‘ and Machines 11 Trusses...

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Unformatted text preview: -‘ Trusses, Frames,‘ and Machines 11 Trusses, Frames, and Machines 10kN 15kN 20kN IOkN 15kN Idealized truss consisting of pin-connected, two-force members with all loads applied at the joints. Two Force member / I“. , r z r Free Body Diagram of all joints & two force members TAB TBC , \ Method of Joints :for solving for unknown forces in 1 members or reactions ) 1000 lb Free Body diagram of Total Truss a.) g P!” 7 ER? . f—”\ “T mm; Method of Joints (continued) Zero-Force Members TAB _ B , _TBC - _ g\__ F: J\ 1 O ; “é .... V ..... g, $~W :7." ’“ I '3 (w ) k (33' ”b u Zero-force members at joints with no external forces applied. Identify the zero-force members present when the trusses shown in the following problems are subjected to the loadings indicated. Use the method of joints to determine the force in en”; member of the truss. Always state Whether each member is in tension or compression. m; TE C31 ET (Leave—r7 0W5 @ZM‘Az-MO «C(W.$1‘ QA‘QTKBOOOL‘Q—I-CBC} QSTJF Lf'o $T>:® MW T ~i ~300©L~b+£g+At :2; 0 V30001b ”Booohb+1‘9\§o w/fibnwtazg A3: 750.1,. “as 1‘ =- o “Ftw‘thngzO ~— FFJQQO'OEO #92150 nu) k: (IAN) .030 1" [“—-*-—--——- k“ .t (a 0113:3ch If ,, F03; =' 359527433 “97%”.30 :2 ....... MO \ s a * <9 — 432(Q‘929mm30 2F? A O . _ o If} @ivsm @Zpy 1'; Z) We glans/Lb - FAD-“$0 FAD: it! égysfltgg‘il" $35.19 Lb ‘ D FAD k 50001. b J- “I Fgfi'lé 00 "b Use the method of joints to determine the forces in truss members CD & BC FROM FBD TQQSSCRLL') ' 8kN MD: Afiehcajso —(noé~3k3mfiws)) ”(E‘KIQCE’M w; {:3 @29- =0 3 x -- 7.3 mtg—+5 56742:“ //Mm ‘ka f {vi/F’B D 045 Tom!” (‘56). ' v 7A}; E: D D FEE \ ,W/JM“ ”FEDD Off SO‘éj-VA D E W’ M.” f" ‘3 F7; «- C) E 7XEQNWS&}* D ’U ““ o A E M i 7 ED «9 33am w COM? “ Tm -\~ (6.67%; at Q, “TR3=«197K~ 7 Comp 2.. O 1’ 1:9-.CKN-vgk 707— xiv/rkg/,MWH F 0*!OKN“(, 74(07X7o7): a k Tic L, E‘LCZE'I, “‘50 (71.3,? B 77545 = 9567 f._ *-~«¥ , FED C38» T‘mw‘T B $31 Calculate the forces in Mt «Jers CD, DG, CG. The mass of the truck is 3500 kg and it’s CG. Is (Lire meter in front of the rear wheels. ,2 “m“ ‘ ",r. FlSD ALL‘ STQU CT ufi: / FG~$3= |375,52.(\] TENS/on, :7." ”D _. Fgfltum) + gsoefiggkgma 0 FE: @5375: N] E: gas-m,“ @F“ 1-: O :9 Fm” FLT,“ 'Ea‘ocfifi‘rfié‘): o Calculate the forces in Menwers CD, DG, CG. The mass of the truck is 3500 kg and it’s CG. Is one meter in front of the rear wheels. FL (:5 010+ Fflfimi) ,. E" 23$} 571%) "71:43 ”A 5;) Simon) +8 33¢(1m\;_g‘300m)¢6 E [d m \ 33,711 r ...
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