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Unformatted text preview: 2-6 Modern Physics Concepts Chap. 2 A 1 MeV photon is Compton scattered at an angle of 55 degrees. Calculate (a) the energy of the scattered photon, (b) the change in wavelength, and (c) the recoil energy of the electron. Solution: (a) FromEq. (2.26)
meC2 :E'=:E+ = 1.835 MeV-I, Thusthe scatteredphotonenergyis E' = 1/1.835= 0.545 MeV. (b) FromEq. (2.25)we have = 1.04 X 10-12 m. (c) The kinetic energy of the recoil electron is Er = E -E' 0.455 MeV. = 1 -0.545 + 2moc2,
But T = mc2 -mOc2 so the above result can be written as p= ..fT
c + moc2= -Ifym;;..jl + (m/mo). Finally, use of the de Broglie relation). = hip in the above result gives !!!:mo -1/2 July 24, 2002 Jmc2 VT 9. ...
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This note was uploaded on 02/01/2010 for the course ECE 4130 taught by Professor Cady during the Spring '06 term at Cornell University (Engineering School).
- Spring '06