HW3-5 - 3-3 Using the liquid drop model, tabulate the...

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Unformatted text preview: 3-3 Using the liquid drop model, tabulate the nuclear binding energy and the various contributions to the binding energy for the nuclei 40Caand 2o8Pb. Solution: A BASIC program is used to evaluate the terms in text Eq. (3.16). A program listing and results are given below. '-CLS fmt$ program to calculate BE(A)/A from the liquid drop model ####.### = " ### ### ### ####.### ####.### ####.### #.### #####.### ##.###" OPEN "3-5.out" FOR OUTPUT AS #1 PRINT "LIQUID DROP PREDICTION of BE vs A" PRINT" A Z N BEv BEs BEc PRINT #1, "LIQUID DROP PREDICTION of BE vs A" PRINT #1, "A Z N BEv BEs BEc , BEa BEp BEp BE BEa BE Case of Ca-40 A = 40: Z = 20 BEv = 15.835 * A BEs = 18.33 * A -(2/3) BEc = .714 * Z * Z / A -(1 / 3) BEa = 23.2 * (A -2 * Z) -2 / A BEp = 11.2 / SQR(A) BE = BEv -BEs -BEc -BEa + BEp PRINT USING fmt$; A; Z; A -Z; BEv; -BEs; -BEc; -BEa; BEp; BE; BE / A PRINT #1, USING fmt$; A; Z; A -Z; BEv; -BEs; -BEc; -BEa; BEp; BE; BE / A Case of Pb-208 A = 208: Z = 82 BEv = 15.835 * A BEs = 18.33 * A -(2/3) BEc = .714 * Z * Z / A -(1 / 3) BEa = 23.2 * (A -2 * Z) -2 / A BEp = 11.2 / SQR(A) BE = BEv -BEs -BEc -BEa + BEp PRINT USING fmt$; A; Z; A -Z; BEv; -BEs; -BEc; -BEa; BEp; BE; BE / A PRINT #1, USING fmt$; A; Z; A -Z; BEv; -BEs; -BEc; -BEa; BEp; BE; BE / ' A CLOSE END RESULTS LIQUID DROP PREDICTION of BE vs A A Z N BEv BEs BEc 40 20 20 633.400 -214.389 -83.510 208 82 1263293.680 -643.484 -810.286 BEa 0.000 -215.938 BEp 1.771 0.777 BE 337.272 1624.748 BElA 8.432 7.811 July 24, 2002 5. ...
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