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HW10-18-19a-19b - 6-13 18 Estimate the available D-D fusion...

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6-13 18. Estimate the available D-D fusion energy in an 8 ounce glass of water. For how long could this energy provide the energy needs of a house with an average power consumption of 10 kW? Solution: (a) First find the number of deuterium atoms in the glass of water. From Table 1.3, 1 oz = 29.57 cm3. Thus in 8 oz of water we have 8 x 29.57 = 236.6 cm3 of water, or with a density of 1 g/cm3, a mass m of 236.6 g. The number of atoms of hydrogen N H is NH = 2NH 0 = 2~ = 2(236.6)(6.022 X 1023) = 1.583 X 1025 atoms. 2 AH20 18 From Table A.4, the atomic abundance of deuterium in elemental hydrogen is 0.015%. Thus, the glass of water contains ND = (0.00015)(1.583 X 1025) = 2.375 X 1021 atoms of deuterium. From Example 6.6, we see that each atom of deuterium, when fully fus- sioned to produce 4He, has a fusion energy potential of ED = 23.82/2 = 11.9 MeV. Thus the D-D fusion energy potential in an 8-oz glass of water
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