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Unformatted text preview: K(Gyjh) = KE(J) of beta particles released per h per kg of air = [decays per hour per L][av. beta KE(J) per decay]/[kg of air/L] ,= {(2.3 X 1012 CijL)(3.7 X 1010 decays per sjCi)(3600 sib)] x [(5.37 keY jdecay) (1.602 x 1016 JjkeV)]j[0.0012 kgjL] = 2.196 x 1010 J kg1 h1 = 2.196 X 1010 Gyjh 22.0 nGy Ih. Note that for this infinite homogeneous medium, the rate of energy emitted by all radioactive sources in a unit mass must equal the radiation energy absorbed in a unit mass. Thus the kerma rate equals the absorbed dose rate. July 24, 2002...
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This note was uploaded on 02/01/2010 for the course ECE 4130 taught by Professor Cady during the Spring '06 term at Cornell University (Engineering School).
 Spring '06
 CADY

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