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(b) Similarly, from Table 9.13 (Case 2) we see the number of cancer deaths
from natural causes
is
1
250 X 106 people
6
Nnat = (20,560+ 17,520)
5
1
= 47.6 x 10 deaths.
2
10 peop e
For a static population with an average
life span of 73.1 years, the annual
natural cancer death rate is then
'
47.6 x 106 deaths
K
Nnat =
,
= tJ.51 X lUu per year.
73.1 y
12. A radiology technician receives an average occupational dose of 0.3 rad per year
over her professional
lifetime. What cancer risk does she assume as a result of
this activity?
Solution:
Use the risk estimates for Case 3 of Table 9.13 for this problem. From this
table we see a female occupation worker has a risk of 3070/105 for an exposure
of 1 rad per year for each year of her working lifetime. Thus her probability of
dying from radiogenic cancer for an annual dose of 0.3 rad/y is
~
)
105
0.3 fad
1 fad
= 9.2 X 103.
risk =
Thus her risk is about one chance
in 110 or about 1 %.
13. A male reactor operator receives a whole body dose equivalent of 0.95 rem
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 Spring '06
 CADY

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