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Unformatted text preview: Solution: NOTE: In the text the period is incorrectly given as 2 s. This is physically impossible. The correct period should be 200 s. (a) First find the change in keff needed to produce the given period. From Eq. (10.17) we find 8k = .BTIT, where for 235u .BT = 0.083 s. Thus keff after the rod insertion is keff = 1 + ok = 1 + pr T (b) The reactivity insertion, from Eq. (10.14), is 0.999585 10.0065 0.999585 = 0.0639($). July 24, 2002...
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This note was uploaded on 02/01/2010 for the course ECE 4130 taught by Professor Cady during the Spring '06 term at Cornell University (Engineering School).
 Spring '06
 CADY

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