This preview shows page 1. Sign up to view the full content.
Unformatted text preview: calculated value above. 13. Discuss possible environmental, technical and political problems associated with each of the disposal options listed in Table 11.6. Solution: This is best left as a classroom discussion topic. 14. A nuclear drive in a submarine delivers 25,000 shaft horse power at a cruising speed of 20 knots (1 knot = 1.15 miles/h). If the power plant has an efficiency of 25%, how much (in kg) of the 235U fuel is consumed on a 40,000 mile trip around the world? Solution: The voyage would take ~t = 40000 (mi)/(20 x 1.15 (mi/h)) = 1,739 h = 72.46 d. The thermal energy required for the voyage is Pshaft (HP) 11 x 745.7 (WjHP) x ~t Eth = From page 149 we find that for 1 MWd of fission energy, 1.24 g of 235U must be consumed. Thus the mass of 235U consumed on the voyage is M(235U) = Eth X 1.24 = 6.70 kg. July 24, 2002...
View Full Document
- Spring '06