Mech320-Assign-3-Solutions

Mech320-Assign-3-Solutions - A'Sf/‘Damga + So/ué‘oh S...

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Unformatted text preview: A'Sf/‘Damga + So/ué‘oh S Zé/Zoo‘3. 91% re we ate. we, was 16$! v.1“ a. “JAN. phi? N '. I we 01‘ affirm CL “ /(kQ flko 6’?“ a}, :0: \ fl Ev?"a (oh/{RU‘GZQ ~—> Eat? :oi—Vo‘? G) AVKCDI 0'1 " it é-+VC)} C9 A SYI'QK #3 ’ S‘D/V‘H‘DL‘ g ’flkoé/(A 3.119;. 9 ‘ ass‘m" flea Shes: 1 CohaflI/{ok‘ 5x Orcslk (0/0)” ””’”““’x / CNka 55 1’ xlyL—‘pyq KL L 4 a LVLOLQ ~ V / loaopILé/hgl lflylL Us)", Ag ‘k OH Le ‘ r J /F( A 0/ 34" ff (9" ¢/ giwe‘ (3/ 475,3 1? .: &1q5 J‘L 'XL 1...]. ) 0k 92" t 57" “(1 e9”) - r) W I 1 _ fl, 3 ’ Z: ( ll (97 ) {0} = 2’»: (XL—Z???) a _, M _ r) / Z L J and” ZEL(TI? —— [MW l” 7. A HM * 2.. 5 5x7. ,1 (12 ’ 3:3} ’51)); (7 2 Ifl/OUPK 3.1(93 dfivlsééukw—x 0)! 5F horWJ 3414:: 03¢ (9/0) /’4 QWIVOJC 07‘ (C9?) “[50 149k: 51:32? 4 6L1_,_ 1'? 74f lfl/m—v. Sling? WC Arc»? ejx/ajz‘Dl—J 0/ «ZN/MW‘M we 0:474; eféé/leé 71 11¢. “I A”... .22, /./O;' 90: 9a: : JDuL f 9/ + g 0' Jan. (22/ 3 7L0 eykr)’ #«Je A .1849»: 0’5 0L max \f‘ wa ncéaz A) use : / @ “Hangs-Auk max/Jinn @ 97:5H é/fi‘V/‘zccwd~ NAAVH ,1 v4/ fl/“é SJRfI/ we khan—u OIL 3%“..[Ex + V See 95, E A” 3.62. a} : I—YL [23’ + yak] “(636) 7:1; 1 C7yx) awe we 0% Fl; :2. 0/ to; U 0.: Suéfli : 735,:[E“”3D+ Gib. 7%; iEV-rVEuj)-? 67 :{X we JCIAQW & S‘LVZ;gé¢/I§SF/4(FMLIL NAbegLP/f 4%: Ju 5 ti 9‘) Jr (33L / a” :’ 1".“ a; -.. a; ax / y") 2W) {x f 2()+VXV)91V‘ Tagfaw- =0 (NW/)(l—V) ‘9’“ (H‘VXI~V3 919;» ‘97 J19? ' 41/3; 1% {agar + 9% ¢ arm I“ My 92’- My 7* )K orJI/ 1-0 W AIS ekaz‘Og 74PM \\ I / wt, rwhl 9/:qu ’ JP" 5F: 1 2. /€1L a z __) we heefig c\/ Guf— vhf Aave K. a: L «=0u-t—Q 1—» 2, Z 2— z—v 9‘ T3“'“"” 73“)“ (7:3 ‘32 °‘ (2: 2—114)“ l-V 62-: z+v RCA !-V Z . viii-r £1)- cit—V. +91K+J1W p“: “w 41 g 4 Jam; 21) )dlv— f_k | I~V 019'} = 2V :47): /+V fiv- l-V+ I~V I—v 01c)? Cghkkvfi I“: Six)! 40k I (D . ASS} ‘m—‘zuarm WMé/(A 75 3.9%: 0\ {gm 5 ax, flSKI‘ju/«ml #2, fo/Ju‘bl. s' lfOV Tor e : _____,_____,Z:;__ -—-—~r Fmfl Shes; 50“ (flw’iké‘w. 1401m— ,' U56 yCA/(C e, m/ \/%=‘/‘f;fi,‘f,i : Iozz. L _ 120 g / Fa’fi 5/18 C L/V‘VQ OI U952 V‘EOG€/l5 homojrayflL/ (Ma 74:61 VQOVZA’Q) 6: 2» mm W; 3 2T :_ 2mon _ ,0 M 77:27 77—(0J20M3... I. o“ ‘W 47.“: Z7. 5 00 MAX 544455 1" @prfid) ' Wok/“~41 r 2' 70*?63: 3.9%., =19 Ammmmm» .: F0” /MOV"\K'—L‘/’.‘ pap/5&1 37’ka (oHCPl-wénvé'ok 42%.“ ' Ufa $6416 7A CUKVC 7. 3. >70 mg V004" OF ho1L¢L ‘ 1 To/ Mew 3 ‘ -——-:v / wwmwflrimJ D 7.20/14 * f.— L Lia/‘14 4 Uc ‘\ 0/ 5+r€($ #47,» 7Lth /o}b‘4 }5: 5. 30 2. 20 2,20 (,0 or“; g; (,(g/ 1L1 [haw/e #145”; «keg 07/2 7* (BEE—+9): (7'7:'°)L+@.zo)7’ mmmmmmwfim_ mm.u_mW~ - gum * “‘m-ufiguw‘ @Y—I/r’kdlflz GR 0‘; g L/vb/ J :_ — /a/ 1 M _‘ > n / L \ flroé/FK 1‘12 — (OI—\A’km’yé.’ @ @ flan-wk J‘LOW 'I’L-«I; Fag 6e 5%} as); (e; LIB): SOLUTION (4.1 1) R P yTA 1.2m l P 4— “’—"X T T M T We have P = 50R, T = 0.8R, and M =1.2R. Stresses are 0,, = 32” = “"3” = 97,784.8R 7.213 7110.05)3 __16_T_:1_6(_‘fl£)_=_ r— M, — Mm), 32,595R 0' - 4%— : 25,464.8R ‘ _ n(o.05)’/4 ox = a", +0), =123,249.6R ( 3) Equation (4.8a): 26°90 ’ = R[(123,249.6)2 + 4(—32,595)2 ]7 or R=932N (b ) Equation (4.93): 130 x10‘5 = R[(123,249.6)2 + 3(—32,595)2 ]% or R = 959 N SOLUTION (4.14) We have (0”, )a” = = 68.33 MPa. Referring to Appendix B: 0'1 = 63.44 MPa 0'2 = 0.533 MPa 0'3 = —12.17 MPa (a) Using Eq. (4.1), 0'”, = l63.44+12.17| = 75.6>68.33: Failure occurs (b) Applying Eq. (4.4b) 20;, = (63.44 — 0.533)2 + (0.533 +12.17)2 + (—12. 17 — 63.44)2 or a",p = 70.13 >68.33: Failure occurs SOLUTION (4.21) Principal stresses are o—L2 = woo + 20) :t [(90)2 + (1502 )fi 01' 0'1 = 284.9 MPa 0'2 = ~64.9 MPa (a) 284.9:13—0, n=1.47 64.9=i§9, n=6.47 (b ) Equation (4.12a): 28.4.2. _ :64_.9 _ .L 420 900 n Solving, n=1.33 ...
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This note was uploaded on 02/02/2010 for the course MECH 320 taught by Professor Dechev during the Spring '08 term at University of Victoria.

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Mech320-Assign-3-Solutions - A'Sf/‘Damga + So/ué‘oh S...

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