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Unformatted text preview: Effects on v max Effects on K M No inhibitor V max = k 2* [E T ] therefore only changes with the change in [E T ] MichaelisMenten constant Intrinsic property of SE relationship, therefore never changes Competitive inhibitor Since no effect on [E T ], no change in v max either Constant, but with competitive inhibiter we have K apparent =αK M and it may seem like K M changes, but instead we observe a k 1 k 2 k1 k2 @ 1/2v max → K M = [S] αK M = apparent K M (observed K M ) new (apparent) K M (which is based on real K M ) Irreversible inhibitor Decrease in v max since inhibitor inactivates E (resembles decrease in [E T ]) NO!! K M never changes (you should know this by now ) Note: since v max is also effected the relationship @ v = 1/2v max → [S]=K M still holds true...
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 Winter '09
 Dr.Klevit
 Catalysis, Enzyme inhibitor, apparent km

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