ME360Homework02Answers

- Homework#2(2/1 Answers ME 3600 Control Systems 1 E2.2 2 E2.11 R = 135.3 T 50 a f = 0.015 x = 3333 x so k = 3333(N/m 40 b f = 0.02 x = 2000 x so

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Homework#2 (2/1) Answers ME 3600 Control Systems 1. E2.2: T . R Δ = Δ 3 135 2. E2.11: a) () 50 0.015 3333 , so 3333 (N/m) fx x k Δ= Δ = b) 40 0.02 2000 2000 (N/m) fxx k Δ = c) 14 0.04 350 350 (N/m) x k Δ = 3. E2.17: a) ( ) 00 0 0 1, 2.4 , 2, 13.2 xy x y == = = b) { } { } 5.2 , 2, 17.8 x yx x y x = Δ = Δ 4. P2.5: a) Define 2 1 P P R = ; Operating point = R o = ( P 1 -P 2 ) o R P P K Q R R Δ = Δ = o 2 1 2 b) When R o = ( P 1 -P 2 ) o = 0, no linear model exists. 5. E2.25: 11 1 2 m x kx kx F t +− = ±± 22 2 1 0 mx kx kx +−= ( 1 x and 2 x are measured from the equilibrium positions.) 6. P2.2: ) ( ) ( 2 12 1 12 1 1 1 1 t F y k y k k y b y M = + + + ± ± ± 0 2 12 1 12 2 2 = + y k y k y M ± ± ( 1 y and 2 y are measured from the equilibrium positions.) 7. P2.3: ) ( ) 2 ( 2 1 1 t F Kx x K x M = +
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This note was uploaded on 02/02/2010 for the course ME 3600 taught by Professor Kamman during the Fall '09 term at Western Michigan.

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