solution1008

# solution1008 - ikram (ai2734) – hw1008 – Swinney –...

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Unformatted text preview: ikram (ai2734) – hw1008 – Swinney – (58785) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. These problems apply the conceptz of Po- tential Energy and the Conservation of En- ergy Principle, which are crucial in all areas of science and engineering. In addition, some the problems in this homework illustrate that insight into the behavior of a system can of- ten be gained from graphs of the potential energy as a function of a parameter (usually position). 001 (part 1 of 3) 10.0 points A 1.48 kg ball is attached to a ceiling by a 1.38 m long string. The height of the room is 3.44 m. The acceleration of gravity is 9 . 81 m / s 2 . What is the gravitational potential energy associated with the ball relative to a) the ceiling? Correct answer:- 20 . 0359 J. Explanation: Basic Concept: U g = mgh Given: m = 1 . 48 kg h 1 = 1 . 38 m g = 9 . 81 m / s 2 Solution: U g = mg (- h 1 ) = (1 . 48 kg)(9 . 81 m / s 2 )(- 1 . 38 m) =- 20 . 0359 J 002 (part 2 of 3) 10.0 points b) the floor? Correct answer: 29 . 9087 J. Explanation: Given: h 2 = 3 . 44 m Solution: U g = mg ( h 2- h 1 ) = (1 . 48 kg)(9 . 81 m / s 2 )(3 . 44 m- 1 . 38 m) = 29 . 9087 J 003 (part 3 of 3) 10.0 points c) a point at the same elevation as the ball? Correct answer: 0 J. Explanation: Given: h 3 = 0 m Solution: U g = mgh 3 = (1 . 48 kg)(9 . 81 m / s 2 )(0 m) = 0 J 004 10.0 points A student in Denver (altitude = 1 mile = 1609 m above sea level) brings a physics book of mass 1 . 9 kg to the top of a ten story building...
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## This note was uploaded on 02/02/2010 for the course PHY 301 taught by Professor Swinney during the Spring '07 term at University of Texas.

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solution1008 - ikram (ai2734) – hw1008 – Swinney –...

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