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Unformatted text preview: ikram (ai2734) hw1015 Swinney (58785) 1 This printout should have 6 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points Planet X has seven times the diameter and seven times the mass of the earth. What is the ratio g X : g e of gravitational acceleration at the surface of planet X to the gravitational acceleration at the surface of the Earth? Correct answer: 0 . 142857. Explanation: Let : M x = 7 M e and R x = 7 R e . mg e = GM e m R 2 e g e = GM e R 2 e . Similarly, g x = GM x R 2 x . The ratio is g x g e = M x R 2 e M e R 2 x = 7 M e R 2 e M e (7 R e ) 2 = 1 7 = . 142857 . 002 (part 1 of 2) 10.0 points G is the universal gravitational constant. g is the free fall acceleration at Earths surface. R E is the mean radius of the Earth. M E is the mass of the Earth. Very near the Earths surface, the gravita tional attraction of the Earth on a body of mass m can be stated in terms of either g or G ....
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This note was uploaded on 02/02/2010 for the course PHY 301 taught by Professor Swinney during the Spring '07 term at University of Texas at Austin.
 Spring '07
 Swinney
 mechanics, Mass

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