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Homework3 - MAE118A: Introduction to Energy Systems...

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Unformatted text preview: MAE118A: Introduction to Energy Systems Homework 3 Kowsik Bodi November 16, 2009 Problem 5.1 Power: P = 1000 MW Efficiency: = 0 . 35 Fuel Heating Value: q = 30 MJ/kg 1 kg of fuel : 0 . 02 kg of S + 0 . 01 kg of N 2 + 0 . 10 kg of Ash + 0 . 87 kg of CH a. Electricity Output: Q = P T = 1000 10 6 365 24 = 8 . 76 10 9 kWh/y b. Coal Usage: M = Q q = P T q = 10 9 365 24 3600 . 35 30 10 6 = 3 10 6 ton/y c. 1 kg of S 2 kg of SO 2 M SO 2 = 2 M S = 2 . 02 M = 2 . 02 3 10 6 ton/y = 1 . 2 10 5 ton/y d. 1 kg of N 3.28 kg of NO 2 from fuel alone 2 3 . 28 kg of NO 2 in total M NO 2 = 2 3 . 28 M S = 2 3 . 28 . 01 M = 2 3 . 28 . 01 3 10 6 ton/y = 2 10 5 ton/y e. 1 kg of fuel 0.10 kg of fly ash M ash = 0 . 10 M = 0 . 10 3 10 6 ton/y = 3 10 5 ton/y 1 Problem 5.2 1 kg 2 . 205 lbs, 1 J = 9 . 4782 10- 4 Btu. M SO 2 Q = 1 Q 2 . 02 Q q = 3 . 81 10- 9 kg/J = 8 . 86 lb/MBtu M NO 2 Q = 1 Q 2 3 . 28 . 01 Q q = 6 . 25 10- 9 kg/J = 14 . 5 lb/MBtu Compared to the 1970 values, SO 2 emissions have increased 7 times, and NO 2 emissions have increased 20 times. Problem 5.3 Power: P = 1000 MW Efficiency: = 0 . 35 Capacity factor: c = 0 . 90 Fuel Heating Value: q = 30 MJ/kg Coal Consumption rate: M = P c q CH + 5 4 O 2- CO 2 + 1 2 H 2 O From the above reaction, 13 kg of CH requires 40 kg of O 2 . = 40 4 . 319 kg of air. Since Coal is being burnt in 20% excess air, air mass is 1 . 2 4 . 319 40 / 13 kg ( 16 kg) per 1 kg of Coal....
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This note was uploaded on 02/03/2010 for the course MAE MAE118A taught by Professor Kowsikbodi during the Fall '09 term at UCSD.

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Homework3 - MAE118A: Introduction to Energy Systems...

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