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# HW 5s - NW 5 Solutions 2.38 202780 = 80x20/100 = 16 6/1'12...

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Unformatted text preview: NW 5 Solutions 2.38 202780 = 80x20/100 = 16, 6/1'12 = 6x12!18 = 4 The circuit is reduced to that shown below. 50 609 3m (4 + l6)/f60 = 20x60I80 = 15 RM =15f115+5=125 Q 40 I, = —— = 3.2 Rec 2.41 Let R0 = combination of three 129 resistors in parallel 1 1 1 1 —-=——+——+— ——> R°=4 R0 12 12 12 Req = 30 + 60||(10+R0 +R) = 30+ 60||(14+R) 50=3o+m ——>74+R=42+3R 74 +R or R = 16 9 3.2 At node 1, v—1+31— =6+v1_v2 (1) 10 5 2 At node 2, V—2 =6+3+v1_v2 (2) 4 2 Solving (1) and (2), v1=_0_\va=12V 3.4 At node 1= 4 + 2 = v1!(5) + v1/(10) —’ v1: 20 At node 2= 5 - 2 = V2/(10) + v2/(5) —> v2 =10 i1 = v1/(5) = 4_.5_= i2 = v1/(10) = 2A: is = Wm) = Q, i4 = V2/(5) = 24; ...
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