{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW1s - Hw 1 Solutions 1.1(a q = 6.482x1017x-1.602x10'19 C...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Hw 1 Solutions: 1.1(a) q = 6.482x1017x [-1.602x10'19 C] = -0.10384 C 1.2(a) i = dq/dt = 3 mA 1.2(e) 1 =dq/dt = —40e‘4'[2cos(50t)+255in(50t)]pA 1.3(a) q(t)= ji(t)dt+q(0)= (3t +1) c 1.3(b) q(t)= j(2t+s)dt+q(v)=(t2 +5t) mC 1.3(d) 1063'aot t = 10 '3°‘sin40t+ 0 =—— —305' 40t-40005t q” I e ‘10 900+1600( m ) = —e'3°t(0.1600340 t+0.12 sin 40t) C 1.4 q=it=3.2x20 =i4_§ 25A, 0<t<2 1.7 i=—= -25A, 2<t<6 25A, 6<t<8 which is sketched below: i(1) 25 A l in sec to U1 ,2 1.9 (a) q= jidt: I10dt=fl§ 3 5x1 = idt=10 1+ 10—— +5 1 b)q I) x ( 2) x =15+7.5+5 = 22.5C ( (c) q=fidt=10+1o+10=3 c ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern