# HW1 - The resistivity of aluminum is 2.6x10-8 Ω.m 4(a Find...

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DEPARTMENT OF BIOMEDICAL ENGINEERING PHOUTHAKANNHA NANTHARATH BIO-ELECTRICITY, BMEN 3201 HOMEWORK # I 9/19/2008

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BMEN 3201 Homework #1 Due date: September 19, 2008 1. How many electrons pass through the filament of a 60 W, 120 V light bulb per second? Charge of an electron is -1.6 x 10 -19 C. 2 . A 60 W hall light is left on continuously. At \$0.12 /kWh, find the cost per week.
3 . Find the resistance of 10 m long, 0.1 mm thick (diameter) aluminum wire.

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Unformatted text preview: The resistivity of aluminum is 2.6x10-8 Ω.m. 4 . (a) Find the equivalent resistance of the circuit shown in Fig.1. (b) If a potential difference of 20 V is applied to the circuit, find the current in each resistor. R1 = 10 Ω R2 = 6 Ω R3=R4 = 4 Ω R5=R6 = 2 Ω 5 . Find the currents in the resistors of the circuit shown in Fig.2 using KCL and KVL. Show the actual current directions....
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HW1 - The resistivity of aluminum is 2.6x10-8 Ω.m 4(a Find...

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