APSC 150 Biological Engineering Tutorial Solutions APSC 150: Engineering Case Studies Assignment #1-Conceptual Process Design a)Example solution (some examples of solutions that you may have proposed and rating criteria that you may have used). Methanol Removal Method Evaluation Criteria Filtration Boiling Absorption Bacteria Eat it i) Easy 5 3 ii) Needs $$$ Equipment 2 1 iii) Enviro Friendly 3 1 iv) Able to Do job 1 5 v) Skilled People 4 1 vi) vii) Total score 14 11 Markers: Please note that assignment 1 was just meant to get the students to brainstorm alternative methods for solving the given problem. The marking of their solutions, and associated decision matrices, is going to be subjective. Assignment #2 Solution #1. a)C5H7O2N + 5O2→5CO2+ 2H2O + NH31 mole of bugs need 5 moles of O2113 g of bugs need 5×32 = 160 g of O21 g of bugs need 1.42 g of O21 mg/L of bugs requires 1.42 mg/L of O2(COD) b)HOOCC6H4COOK + 15/2 O2→7CO2+2H2O + KHCO312 8 x C = 96 16 4 x O = 64 5 x H = 5 K = 39204
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APSC 150 Biological Engineering Tutorial Solutions 204 g KHP need 240 g O2x g KHP need 500 g O2x = 425 ∴425 mg/L KHP has COD of 500 mg/L #2. CH3OH + aO2+ bNH4++ cHCO3-→dC5H7O2N + eCO2+ fH2O C 12 C560 4H 4 H77 O 16O232 32 N 14113 If yield is 0.42 (class example): i)Calculate d d==××=ethanolmolebiomassmole0.12biomassg113biomassmole1methanolmolemethanolg23methanolgbiomassg0.42YX/Sii)Calculate b b = 0.12 iii)Charge balance c = 0.12 iv)Calculate f LHS RHS H 4.6 (7X0.12) + 2f ∴f = 1.88 v)Calculate e C 1 + 0.12 (0.12x5) + e ∴e = 0.52 vi)Calculate a O 1+2a+0.36 (0.12x2)+(0.52x2)+1.88 ∴a = 0.9