APSC 150
Biological Engineering Tutorial Solutions
APSC 150:
Engineering Case Studies
Assignment #1Conceptual Process Design
a)
Example solution (some examples of solutions that you may have proposed and rating criteria that you may
have used).
Methanol Removal Method
Evaluation
Criteria
Filtration
Boiling
Absorption
Bacteria
Eat it
i) Easy
5
3
ii) Needs $$$
Equipment
2
1
iii) Enviro
Friendly
3
1
iv) Able to
Do job
1
5
v) Skilled
People
4
1
vi)
vii)
Total score
14
11
Markers: Please note that assignment 1 was just meant to get the students to brainstorm
alternative methods for solving the given problem.
The marking of their solutions, and
associated decision matrices, is going to be subjective.
Assignment #2 Solution
#1.
a)
C
5
H
7
O
2
N + 5O
2
→
5CO
2
+ 2H
2
O + NH
3
1 mole of bugs need 5 moles of O
2
113 g of bugs need 5
×
32 = 160 g of O
2
1 g of bugs need 1.42 g of O
2
1 mg/L of bugs requires 1.42 mg/L of O
2
(COD)
b)
HOOCC
6
H
4
COOK + 15/2 O
2
→
7CO
2
+2H
2
O + KHCO
3
12
8 x C
= 96
16
4 x O
= 64
5 x H
= 5
K
= 39
204
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APSC 150
Biological Engineering Tutorial Solutions
204 g KHP need 240 g O
2
x g KHP need 500 g O
2
x = 425
∴
425 mg/L KHP has COD of 500 mg/L
#2.
CH
3
OH + aO
2
+ bNH
4
+
+ cHCO
3

→
dC
5
H
7
O
2
N + eCO
2
+ fH
2
O
C
12
C
5
60
4H
4
H
7
7
O
16
O
2
32
32
N
14
113
If yield is 0.42 (class example):
i)
Calculate d
d
=
=
×
×
=
ethanol
mole
biomass
mole
0.12
biomass
g
113
biomass
mole
1
methanol
mole
methanol
g
2
3
methanol
g
biomass
g
0.42
Y
X/S
ii)
Calculate b
b = 0.12
iii)
Charge balance
c = 0.12
iv)
Calculate f
LHS
RHS
H
4.6
(7X0.12) + 2f
∴
f = 1.88
v)
Calculate e
C
1 + 0.12
(0.12x5) + e
∴
e = 0.52
vi)
Calculate a
O
1+2a+0.36
(0.12x2)+(0.52x2)+1.88
∴
a = 0.9