HW-7 - Rahman, Tarique Homework 7 Due: Oct 16 2007,...

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Rahman, Tarique – Homework 7 – Due: Oct 16 2007, midnight – Inst: Vandenbout 1 This print-out should have 20 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. Here are more questions fnishing up Chap- ter 14. Remember, the HWS could be over- loaded when the actual due time arrives Tues- day night. Room Assignments For EXAM 2 A-K WEL 1.316 L-O WEL 2.122 P-Z WEL 1.308 001 (part 1 oF 1) 10 points sp 2 hybrid orbitals have 1. linear symmetry. 2. trigonal bipyramidal symmetry. 3. tetrahedral symmetry. 4. trigonal planar symmetry. correct 5. trigonal pyramidal symmetry. Explanation: 002 (part 1 oF 1) 10 points In the molecule, C 2 H 4 , what are the atomic orbitals that participate in Forming the sigma bond between the C and H atoms? 1. H: 1 s and C: 2 p 2. H: sp 2 and C: sp 2 3. H: 1 s and C: sp 2 correct 4. H: 1 s and C: sp 5. H: 2 p and C: sp 3 Explanation: The electrons in the H 1 s orbital and the electrons in the C sp 2 hybrid orbital partici- pate in Forming the bond. 003 (part 1 oF 1) 10 points A sigma bond 1. may exist alone or in conjunction with a pi bond. correct 2. is composed oF non-bonding orbitals. 3. always exists in conjunction with a pi bond. 4. is always polar. 5. stems From sp hybridization oF orbitals. Explanation: A sigma, or single bond can exist by itselF or with a pi bond, Forming a double bond. 004 (part 1 oF 1) 10 points In a new compound, it is Found that the cen- tral carbon atom is sp 2 hybridized. This implies that 1. carbon is also involved in a pi bond. cor- rect 2. carbon has a tetrahedral electronic geom- etry. 3. carbon has Four regions oF high electron density. 4. carbon has Four sigma bonds. 5. carbon has Four lone pairs oF electrons. Explanation: Carbon Forms Four bonds. sp 2 hybridiza- tion enables a C atom to bond to three other atoms, leaving one electron in a p orbital, which will Form a pi bond. 005 (part 1 oF 4) 10 points Draw the Lewis structure For the Following hydrocarbon molecule. The carbons are num- bered one to Four starting with the Far leFt
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Rahman, Tarique – Homework 7 – Due: Oct 16 2007, midnight – Inst: Vandenbout 2 carbon as one.
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This note was uploaded on 02/04/2010 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas at Austin.

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HW-7 - Rahman, Tarique Homework 7 Due: Oct 16 2007,...

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