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Unformatted text preview: Sterlings approximation ( N is very large!): ln " = ln N ! # 2ln( N /2)! $ N ln N # 2 N 2 ln N 2 = N ln N # ln N /2 ( ) = N ln2 Therefore, the entropy of the binary alloy, with N = 10 23 is: S = Nk B ln2 = 7 " 10 22 k B Another way of seeing this is that there are 2 choices for each of the N slots! b) There is no work, heat transfer, or change in temperature, so the change in internal energy should be 0! c) If, on the other hand, A and B were not distinct from eachother, there would only be 1 way of putting all the particles into the N slots! So, S = 0....
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This note was uploaded on 02/04/2010 for the course PHYSICS 7B taught by Professor Packard during the Spring '08 term at University of California, Berkeley.
 Spring '08
 Packard

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