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Unformatted text preview: Answer: b 1 b 2 V 0 g) We now connect the outer and inner surfaces of the larger conductor to a battery, with voltage V . If the resistivity of the conductor is , find the current. The effects of the small hole at the top of the conductor can be ignored. (Note: here is the resistivity, not the charge density!) Answer: R P 3) (20 pts.) A uniformly charged disk, with radius R has surface charge density . Find the electric potential at P , located on the rim of the disk. Answer: r R E 4) (20 pts.) In the circuit below, the battery has EMF, E , and internal resistance, r . If we connect this battery to a resistor with resistance, R , show that the power dissipation for R is the greatest when R = r . Basic Integral Table...
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This note was uploaded on 02/04/2010 for the course PHYSICS 7B taught by Professor Packard during the Spring '08 term at University of California, Berkeley.
 Spring '08
 Packard
 Resistance

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