lecture 8

lecture 8 - Electrochemistry If add Zn(s to a solution of...

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Electrochemistry If add Zn(s) to a solution of CuSO 4 , then sponta- neously: Zn(s) + Cu ++ Zn ++ + Cu(s) Thus G ) T , P < 0 Zn(s) dissolves and Cu(s) plates out. An electrochemical cell is a device to extract work, w 0 , from this process. 1
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Electrical work = charge × potential diference w 0 = Q E Joule = Coulomb × Volt where Q is the total charge (Fowing through a cir- cuit) and E is the voltage or potential diference or electromotive ±orce (em±) o± the electrical cell. Note – we use the same symbol ±or charge and reaction quotient. ²or n moles o± electrons Q = - n F where the minus ‘ - ’ sign accounts ±or the negative charge o± the electron, and the ²araday F = 96500 Coul/mole electrons. Then w 0 = - n FE w 0 rev = - n FE rev w 0 We recall dG + SdT - V dP = dw 0 rev dw 0 Integrating ±or constant T, P G ) T,P = w 0 rev = - n FE rev ≤ - n FE actual ( - G ) T,P /n F = E rev is the actual voltage of the cell if it is running reversibly, i.e. drawing no current) . 2
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lecture 8 - Electrochemistry If add Zn(s to a solution of...

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