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Unformatted text preview: + 1 n T. This contradicts the assumption that is the supremum of T . Case 2 : Suppose 2 > b . Let = 2b . Note that ( 1 n ) 2 = 22 n + 1 n 2 22 n . Let n be chosen so that 2 n . Then ( 1 n ) 2 > b. So 1 n is an upper bound of T contradicting the assertion that is the least upper bound. So 2 = b. Q.E.D. 1...
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This note was uploaded on 02/05/2010 for the course MATH 324 taught by Professor Dang during the Spring '08 term at SUNY Geneseo.
 Spring '08
 DANG

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