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Unformatted text preview: PHYSICS 1D03 TEST2 November 17, 2004 Name 3 0 Z M 2L 035 S Instructors: Student Number
A. Jopko (section C01)
N. McKay (sections C02, C03)
D. Venus (section C04) Instructor:
K. Sills(section C05)
Lecture Section: Write your name and student number on your paper before you begin. Multiplechoice questions are worth 2
marks each (only the answer is marked), and problems are worth 3 marks each (clear solutions required).
Only the McMaster standard calculator (Casio fir991') is allowed. Notes and formula sheets are not permitted.
A sheet of formulae is attached at the end of the test paper. If you use them it is your responsibility to lcnow
what they mean and when they can be used. Earth’s gravitational ﬁeld: g = 9.81 Im's2 continued on page 2... Page 2 of 8 pages Part A (multiple choice): Print the letter corresponding to the best or most nearly correct answer in the
box beside each question. Each correct answer is worth 2 marks. 1. A rod has one end at the origin and one end at the point P whose coordinates are (1m, 2m, 2m). A force
F = (3i+2jlk) N acts on the rod at the point P. The torque about the origin due to F is: A 6'+T—4kN ___ J) a A A A A .
)(i:4k))N.: Purl? riik+ieekuia+GJ—4«)Nk C) (6i— Tj +4k)Nrn 4 N
D) noneofthcabove. ‘v‘ (''C(1 +751 '4)! j/U’I'“
HIISWCI' l4 2. A uniform bar of length L weighs 24 N. It rests in a horizontal
position, attached to a hinge at one end, and supported by a vertical wire
attached a distance 3/4 L from the hinge. What is the tension in the wire? I ' a" L A)24N
' 9.9%)ng h——L—*
'2. answer It 3. Four particles, each of mass m, are joined by massless rods to form a square of /
merit of inertia of the square, when it is rotated about a diagonal, is m m B our2 a a . C) 4ma / D) none of the above. [ Q 5 2' m J5 2 m  m
V? / 0
answer Pr continued on next page... Page 3 of 8 pages 4. A pendulum swings back and forth between positions 1 and 5 in the diagram. At which of the positions is the
angular acceleration of the pendulum zero? A) At positions 1, 3, and 5. At position 3 only.
oneo t ea ove.
answer I o a o o
a tar“ “" W “(‘9 ° 5. A constant force F = (2i + 3 j + 4k) N is applied to a particle while it moves from the origin to the point (2m, 2m, 2111). The work done by the force is —") ____) ‘ ' o I J S‘
F '
C) 42+62+82 J D) (22 +32 +42)(22 +22 +21) J answer B 6. A ball of mass 2 kg is dropped and has a velocity of 5 m/s downward just before it hits the ﬂoor. Its
velocity after rebounding from the ﬂoor is 4 m/s upward. The change in the kinetic energy of the ball is A) 1] 10I~2¢T
D ﬂ continued on next page... Page 4 of 8 pages 7. A particle moving on the x axis is subject to a conservative force such that the
potential energy of the particle is given by U(x, y) = 2x + x3 , where x and y are in
metres and U is in joules. When the particle moves from the point (2m, 0) to the
origin along the semicircular path shown, the work done by this conservative
force is A) —12 J __ B) 32 J Us [L4 ‘5 l O— I C) 32J D) +12 I answer D 8. The simple truss shown is supported by a ﬁxed pin at A and a roller
at D. If the weight of the truss members is negligible, is the vertical
member BD in tension or in compresssion when a horizontal load P is
applied at C in the direction shown? I is in tension B) BB is in compressmn
C) ere IS zero orce m ' D.
D) ED is in both tension and compression. answer B 9. A ﬂywheel on frictionless bearings is brought up to speed with constant angular acceleration by an electric
motor, starting from rest at t = 0. Which graph best shows the power required from the motor as a function of
time? totalt 00%
film 2 was”
?:e)f€act continued on next page. .. Page 5 of8 pages Part B (Problems): Write a clear solution showing how the answer is obtained. Each problem is
worth 3 marks. 10. A uniform board of mass M and length L is at an angle of 35° to the horizontal as
shown, with one end on a horizontal ﬂoor at A, and the side resting against the edge of a smooth step at B, twothirds of the the way from the lower end Assume there is no friction at B, where the board rests against the step. Draw a carefullylabelled
freebody diagram for the board, and calculate the numerical value of the minimum
coefﬁcient of static friction between the board and the ﬂoor which will prevent slipping. "5 “*4 Wm M 4 =0 1 saw?) = warmst“ ’3‘ A/B 2' (5/15W3YDJM3 —. (LOW/{J c1) 3. F7: :0 :37 9!; :NB $43? 3 2H1Z§4~3T° @336”)
1' (LBS—GLMJ 3) iii :0 :3 ~43ij ”NB c4335”: MJ(/%¢0513§‘)
= o. 4‘37 H3 C _ 3’/ 91.3”» 3§°
M92 —’°w.__ﬂ—————" “:5 20.708
NA /* 34? “6‘33?“ ——— continued on next page... Page 6 of 8 pages 11. A 2.4kg box slides across a level ﬂoor, hits a spring attached to the
wall, and bounces back. There is friction between the box and the ﬂoor
during the entire motion . The box is initially moving at 5.0 mfs when it is
1.0 m from the end of the spring, and it ﬁnally comes to rest, after
bouncing, at the same position, 1.0 m from the end of the spring. The
maximum compression of the spring during the process is 0.40 111. Use
energy principles to calculate the spring constant. (HIM) continued on next page. . . Page 7 of 8 pages 12. A box of mass M is lifted by a light rope which passes over a pulley of mass M (equal
to the mass of the box), radius R, and moment of inertia V: MR2. The other end of the rope
is pulled with a constant force equal to 1.5 times the weight of the box. The rope does not slip on the pulley. Draw appropriate freebody diagrams, and calculate the acceleration of
the box. Freebody Diagrams Fp = 1.5Mg answer 3,7) “‘41 continued on next page. .. Page 8 of 8 pages 13. A wheel is ﬁxed to a shaft of radius 2.0 cm. A weight of mass m = 64 kg is suspended from
a cord wrapped around the shaft, so that the weight is raised or lowered as the wheel turns. A
motor is spinning the wheel at 360 revolutions per minute, raising the weight at constant speed,
when the drive belt connecting the motor to the wheel breaks. The wheel and shaft have a combined moment of inertia about the axis of rotation of 0.16 kgrnz. They rotate without
friction once the motor belt breaks. Calculate how much higher the weight will rise, after the
belt breaks, to reach its maximum height. taxJ; (4),.— 3521223 37.7 ”/4
W L (,05
(“Log 3 0'75“? “V5 1' i Mi: imm1+%_fw1:/g7,5 4' 3/3573— '3'. answer can END ...
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 Spring '08
 N. MCKAY

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