{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

homework9-solutions1

homework9-solutions1 - ME 104 Homework 9 Solutions Prof...

Info icon This preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
ME 104: Homework 9 Solutions Prof. Karl Hedrick: University of California, Berkeley
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Chapter 16, Solution 88 ( a ) Angular acceleration . Rod AB : 2 2 2 1 12 1 8 lb (2 ft) 12 32.2 0.8282 lb ft s AB AB W I l g eff 3 ( ) : (6 lb)(2 ft) (8 lb)(1ft) 5 B B AB M M I   0.8 lb ft AB I (1) 2 (0.8282 lb ft s ) 0.8 lb ft 2 9.66 rad/s α Entire assembly : Since AC is taut, assembly rotater about C as a rigid body. Kinematics : 2 2 (0.75) 1 1.25 ft 1 0.625 ft 2 BC CB CG CB (0.625 ft) BC a (0.75 ft) AB a Kinetics : 2 2 2 1 ( ) 12 1 5 lb (1.25 ft) 12 32.2 0.0202 lb ft s BC BC W I CB g
Image of page 2
PROBLEM 16.88 (Continued) ( b ) Couple M . eff ( ) : C C M M   2 2 2 (0.5 ft) (0.625 ft) (1ft) 5 lb 8 lb (5 lb)(0.5 ft) (0.625 ft) (0.0202 lb ft/s ) (0.75 ft) 32.2 32.2 BC BC BC BC AB AB AB AB M W m I m I M I a a Substitute 2 9.66 rad/s and from Eq. (1), 0.8 lb ft AB I 2.5 (0.06016)(9.66) (0.0202)(9.66) (0.1398)(9.66) 0.8 2.5 0.5860 0.1950 1.35 0.8 2.5 2.93 5.43 lb ft M M M M   5.43 lb ft M
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Chapter 16, Solution 100 Assume disk rolls: 8 ft 12 a r 2 2 10 lb 6 ft 32.2 12 I mk 2 0.07764 lb ft s I eff 4 ( ) :
Image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern