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homework9-solutions1

# homework9-solutions1 - ME 104 Homework 9 Solutions Prof...

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ME 104: Homework 9 Solutions Prof. Karl Hedrick: University of California, Berkeley

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Chapter 16, Solution 88 ( a ) Angular acceleration . Rod AB : 2 2 2 1 12 1 8 lb (2 ft) 12 32.2 0.8282 lb ft s AB AB W I l g eff 3 ( ) : (6 lb)(2 ft) (8 lb)(1ft) 5 B B AB M M I   0.8 lb ft AB I (1) 2 (0.8282 lb ft s ) 0.8 lb ft 2 9.66 rad/s α Entire assembly : Since AC is taut, assembly rotater about C as a rigid body. Kinematics : 2 2 (0.75) 1 1.25 ft 1 0.625 ft 2 BC CB CG CB (0.625 ft) BC a (0.75 ft) AB a Kinetics : 2 2 2 1 ( ) 12 1 5 lb (1.25 ft) 12 32.2 0.0202 lb ft s BC BC W I CB g
PROBLEM 16.88 (Continued) ( b ) Couple M . eff ( ) : C C M M   2 2 2 (0.5 ft) (0.625 ft) (1ft) 5 lb 8 lb (5 lb)(0.5 ft) (0.625 ft) (0.0202 lb ft/s ) (0.75 ft) 32.2 32.2 BC BC BC BC AB AB AB AB M W m I m I M I a a Substitute 2 9.66 rad/s and from Eq. (1), 0.8 lb ft AB I 2.5 (0.06016)(9.66) (0.0202)(9.66) (0.1398)(9.66) 0.8 2.5 0.5860 0.1950 1.35 0.8 2.5 2.93 5.43 lb ft M M M M   5.43 lb ft M

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Chapter 16, Solution 100 Assume disk rolls: 8 ft 12 a r 2 2 10 lb 6 ft 32.2 12 I mk 2 0.07764 lb ft s I eff 4 ( ) :
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