Phy 9B mt2soln_03 Fall

# Phy 9B mt2soln_03 Fall - Physics 9B-A Midterm 2 Solutions...

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Physics 9B-A Midterm 2 Solutions Cole [1] a) remain the same b) 1 c) larger d) mass e) convection f) increase g) greater h) white i) path difference j) all of the above. [2] (8 pts) The 6th interference max is missing because φ β θ π λ == () 2 = 2 2 62 6 d a sin sin . There are 5 fringes to the right of the central max, 5 to the left and one in the center õ N = 2(5) + 1 = 11. b) (4 pts) The central diffraction maximum goes from ∫ = -2π to +2π where as for the first secondary max ∫ = 2π to 4π. Hence there are only 5 fringes in the first secondary maximum. c) (8 pts) I I o = cos sin 2 2 2 2 2 . At the 4th interference max ƒ = 4(2π) so the cos 2 ƒ/2 = 1. From part (a) ==() 6 4 6 2 õ I I o = = = = sin sin . . . 2 2 2 2 3 2 3 2 2 0 866 209 017 [3] a) (5 pts) There will be a dark fringe because the ray reflected from the bottom surface of the top plate will be inverted since it is hittingoptically denser methyl iodide, but the ray from

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## This note was uploaded on 02/06/2010 for the course PHY 9B taught by Professor Cheng during the Fall '08 term at UC Davis.

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Phy 9B mt2soln_03 Fall - Physics 9B-A Midterm 2 Solutions...

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