{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Assignment 3 -- liaoc4

# Assignment 3 -- liaoc4 - 1P03 Assignment 3 Name Cheng-kai...

This preview shows pages 1–2. Sign up to view the full content.

1P03 Assignment 3 Name: Cheng-kai Liao Mac ID: liaoc4 Student number: 0943980 Date: Nov, 26, 2009 Q1: As we look into Figure 6.5 and Figure 6.6, the magnesium alloys possess the lowest k. The second lowest is aluminum alloys and the highest k value is the high carbon steels. From the equation in Figure 6.5: log p = 1/2 log σ + log K, the p represents the density of that material, and the E represents the modulus of elasticity. The smaller the k value, the smaller the mass of the material, if the E value stays the same. The small mass is what we need to compute. Same pattern for Figure 6.6: log p = 1/3 log E + log K. Therefore, magnesium alloys is the best material choice in the mass consideration. In the graph Figure 6.7 and Figure 6.8, the formulas are log C = 1/2 log σ + log K and log C = 1/3 log E + log K. The two formulas shown above are very similar, for the first formula, C is cost per volume and σ is the failure strength. If given the same σ value, the smaller the K the lower cost it will be. On the other hand, for the second formula, E is the elasticity of the material and C is the cost per volume. The cost will

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern