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Assignment 3 -- liaoc4

Assignment 3 -- liaoc4 - 1P03 Assignment 3 Name Cheng-kai...

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1P03 Assignment 3 Name: Cheng-kai Liao Mac ID: liaoc4 Student number: 0943980 Date: Nov, 26, 2009 Q1: As we look into Figure 6.5 and Figure 6.6, the magnesium alloys possess the lowest k. The second lowest is aluminum alloys and the highest k value is the high carbon steels. From the equation in Figure 6.5: log p = 1/2 log σ + log K, the p represents the density of that material, and the E represents the modulus of elasticity. The smaller the k value, the smaller the mass of the material, if the E value stays the same. The small mass is what we need to compute. Same pattern for Figure 6.6: log p = 1/3 log E + log K. Therefore, magnesium alloys is the best material choice in the mass consideration. In the graph Figure 6.7 and Figure 6.8, the formulas are log C = 1/2 log σ + log K and log C = 1/3 log E + log K. The two formulas shown above are very similar, for the first formula, C is cost per volume and σ is the failure strength. If given the same σ value, the smaller the K the lower cost it will be. On the other hand, for the second formula, E is the elasticity of the material and C is the cost per volume. The cost will
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