EE325_Quiz_2_sol_Yilmaz

# EE325_Quiz_2_sol_Yilmaz - NAME Solution EE325-Fall 2009...

This preview shows page 1. Sign up to view the full content.

NAME: _____________ Solution EE325-Fall 2009 Quiz 2 1) A 1 nC point charge is located at (, ,) ( 0 ,0 ,3 ) xyz = and a -1 nC point charge is located at 0 , 3 ) =− in free space. Find the electric field strength E at ( , , ) (4,0,0) = . Hint: The answer is a vector. (5 points) The position vector for the first charge (the one at 0 ) = ) is 1 ˆ 3 z ′ = ra The position vector for the second charge (the one at 0 ) = ) is 2 ˆ 3 z ′=− The position vector for the observation point is ˆ 4 x = 12 99 33 01 0 2 9 0 00 () 10 10 4| |4 | | ˆˆ 43 10 4 3 | | 4 3 | ˆ 6 10 10 V/m 4 125 125 4 125 xz z πε −− =+ ′′ ⎛⎞ −+ ⎜⎟ ⎝⎠ = Er E r rr aa a 2) Let 22 2 42 4 C / m xy z xy x z yz + + Da a a . What is the electric flux leaving the rectangular parallelepiped 0 2, 0 3, 0 5 m << ? (5 points) See Homework 2 solutions. EE325-Fall 2009 Quiz 2 1) A 1 nC point charge is located at 0 ,4 ) = and a 1 nC point charge is located at 0 , 4 ) in free space. Find the electric field strength E at (3,0,0) = . Hint: The answer is a vector. (5 points) The position vector for the first charge (the one at 0 ) = ) is 1 ˆ 4 z ′ = The position vector for the second charge (the one at 0 ) = ) is 2 ˆ 4 z The position vector for the observation point is ˆ 3 x = 02 9 0 10 10 | | 34 10 3 4 | | 3 4 | ˆˆˆˆ ˆ 6 10 10
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online