hw3 - khounvivongsy(sk27799 – Homework 3 – Weathers...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: khounvivongsy (sk27799) – Homework 3 – Weathers – (17104) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Two sides of a triangle are 18 cm and 29 cm, with the included angle 102 ◦ . a) What is the length of the third side? Correct answer: 37 . 1761 cm. Explanation: Basic Concepts: The Law of Cosines states c 2 = a 2 + b 2- 2 ab cos C The Law of Sines states sin A a = sin C c Solution a c b A C We are looking for the side opposite the given angle so c = radicalbig a 2 + b 2- 2 ab cos C 002 (part 2 of 2) 10.0 points b) What is angle opposite the side 18 cm? Correct answer: 28 . 2684 ◦ . Explanation: sin A a = sin C c A = arcsin parenleftbigg a sin C c parenrightbigg 003 10.0 points A high fountain of water is located at the center of a circular pool as in the figure. A student walks around the pool and estimates its circumference to be 183 m. Next, the student stands at the edge of the pool and uses a protractor to gauge the angle of elevation of the top of the fountain to be 28 . 8 ◦ . How high is the fountain? Correct answer: 16 . 0118 m. Explanation: R h θ The circumference of the pool is C = 2 πR so its radius is R = C 2 π = 183 m 2 π = 29 . 1254 m The radius and the height of the fountain form...
View Full Document

{[ snackBarMessage ]}

Page1 / 3

hw3 - khounvivongsy(sk27799 – Homework 3 – Weathers...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online