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HW1Solutions[3]

# HW1Solutions[3] - i 1(01)rews{y/e mime/z RNA:3 0’2...

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Unformatted text preview: i 1) (01),)rews/{y/e mime/z RNA/:3 0’2 ”QEVﬁh’S/HL )soi’letma/ fI/Lﬂzéfa‘f—lc @723“;sz _M_(C)...-nMon imﬂth/L ) JYMUJL) affmx’mk}wifiiv:f (iii/£2”? (Ci) ”imam“ Me j 17:71:) 77cm; 374.14%: kwlaerl: min? (9) “ex/5;: 4 i [750 rCt;f 1:) (Edgar/Z; Easééwmq/ -;::g.:2___,gmgs;>zz;‘,;;,;w..m.,7q.53;e) 0.0.7.0 Carter 1—5. R = of + b. 0n substimtion of the data. supplied, we obtain 5 = IDUa+b and 0=500a+b, ﬂow which a = 0.00025 (2 deg“ and 0 = 4.75 (2. R—b a We have T = 1 and so whenR = 5.4 Q, T = 260 degrees. Carter 1—6. Wi‘lh x = P11: and y = PIMP, we can eonstmct the following table: it (torr) y 400 1 .2900 300 1 .2860 200 1 .2825 100 1 .2755 A least-squares linear regression of y uponx gives y = 3.65x10‘5x + 1.27525, and so, for P11: = 0, PIPE = 1.27525. Ifwe assume that, in the limit as Pu: —>- 0, TIT“: —>PJ’P1-P, we have T = 1.27525 92': 273.16. That is, T = 343.35 K = 75.20 "C. (331101“ 1—8. 011 substimtion of the data supplied, we obtain 2000! + 400003;! = 60 and 4000 + 16000013 = 40, ﬂ‘omwhjch a = 0.5 111V 0"—1 and 0 = —0.001 mVC°_2 . For 1":— = 30 1111!, we have to solve the quadmtic equation —0.001T2 + 0.51" =30. We obtain T = 430.3 °C or 69.7 "C. 1"?) T =0q+ fc'e, fcl‘vlf' an} M6 4'?“ 5?L€aM/c'22m7” (a) X . ' x 4. >< ~20 T. QT‘t‘L g x; :, k) _) Xj ;: /0(/q 4L 5‘ (( : _/S06. : [500' Xr><2 5 R ‘I‘ :/00 Xs-X,‘ (b) T341~X+L~ =39 %’ O;a//J){;+¢é ) I00: a/an- ﬁ/HX/ 151/145? T Z W— 01/n XI 3 ma Ugh") X: ‘f 0" Y: I“ (Kr/XI) ...
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HW1Solutions[3] - i 1(01)rews{y/e mime/z RNA:3 0’2...

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