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ChemLab113-0012

# ChemLab113-0012 - Solution Step 1 pmp = 0.0653/0.0592 =...

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Unformatted text preview: Solution Step 1. pmp = 0.0653/0.0592 = 1.1030 Step 2. Increase MD to 0.0654 Decrease VD to 0.0590 (note we decrease VD because this results in an increase in p) Step 3. Pmax = 0.0654/ 0.0590 = 1.1085 We see that p has increased by 0.0055, which tells us the uncertainty. Step 4. Rounding to give one signiﬁcant ﬁgure, we report 9 = 1.103 i 0.006 g/mL. Example 3 Calculate and report the value of B with its uncertainty for the following calculation, where x is 3.472 :t 0.003 and y is 3.274 t 0.003. B = x3 - y3 Solution Step 1: The most probable value is calculated. em = (3.472)3 — (3.274)3 = 6.759955 Step 2: The new values of x and y are x = 3.475 y : 3.271 Step 3. The maximum value of B is calculated. 3m = (3.475)3 — (3.271)3 = 6.964925 so the uncertainty of B is AB = 6.964925 - 6.759955 = 0.204970 Step 4: Rounding the uncertainty and the most probable value, we report B = 6.8 i 0.2 20 ...
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