Chemistry 111 Page 1 out of 5 Exam I / Fall 2002 Answer KeyBonus (01 pt): Imagine that the nuclide 14O were to absorb an electron into the nucleus (rather than emit a beta particle). What nuclide would it form? Well, it is absorbs an electron, that is probably something very similar to the beta emission, except backwards. This means that a proton would be converted into a neutron. Therefore, the atomic number would decrease by one, while the mass number would remain the same. 714NShow all your workin the space provided in order to receive any credit at all!1. K3PO4What is the formula for potassium phosphate? (03 pts)2. 1.56 mol Determine the number of moles of oxygen atoms (O) in 25.0 grams of oxygen gas (O2). (06 pts)25.0 g O2×1 mol O232.0 g O2×2 mol O1 mol O2= 1.56 mol O. 3. 7.63 ×1023How many hydrogen (H) atoms are there in 32.1 g of aluminum hydroxide, Al(OH)3, MW = 75.98 ? (10 pts)32.1 g Al(OH)3×1 mol Al(OH)375.98 g Al(OH)3×3 mol H1 mol Al(OH)3×6.022 ×1023atoms1 mol H= 7.63 ×1023H atoms. 4. 17.4 % During a combustion of a 20.0 g sample of an unknown hydrocarbon (a compound that has carbon and hydrogen only), 31.0 g of water are formed. What is the mass percent of H in that hydrocarbon? (08 pts)Well, we need to figure out how many grams of hydrogen are in that water sample. 31.0 g H2O ×1 mol H2O18.02 g H2O×2 mol H1 mol H2O×1.008 g H1 mol H= 3.47 g H.
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