Chemistry 111 Page 1 out of 7 Exam III /Fall 2002 Answer KeyBonusquestion: Name today’s holiday. Hint… Kids go trick-or-treating all over the city and get lots of candy. ☺HalloweenFill in the Blanks. Please, make sure you write your answer in the blank provided. If it requires a calculation, make sure you show all your work, or you will receive no credit for your answer. 1. 67.5 min Let’s say that at the house of a certain math professor, he and his wife hand out 250 pieces of candy in the first 5.00 minutes of a Halloweennight. Of course, the kids are terribly frightened because of his ghoulish disguise but what they do not realize is that he is not wearing a costume… Anyhow, they have all together 2,500 pieces of candy. Assuming that the candy will be dispensed following second order kinetics, how long will it take before they have only the 1,000 pieces he wants to keep for himself? (14 pts)Well, we are told that the disappearance of the candy follows second order kinetics. This means that… 1[A]−1[A]D=k tWe need to determine the rate constant (k) first. For that, we use the information that he dispenses 250 pieces of candy in 5.00 minutes. Therefore, he has 2,250 pieces of candy left after 5 minutes. 12,250 pieces−12,500 pieces=k ×5.00 minutes∴k = 8.89×10-6pieces-1min-1. Now, he wants to have 1,000 pieces left for himself to eat at a later time. Therefore, 11,000 pieces−12,500 pieces=8.89 ×10-6pieces-1min-1×t∴t = 67.5 minutes. 2. H2Both H2gas and butane gas (CH3CH2CH2CH3) are non-polar and they both obey the ideal gas law. Which of these two would you
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