F04_E2A - Chemistry 111 Page 1 out of 7 Exam II / Fall 2004...

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Chemistry 111 Page 1 out of 7 Exam II / Fall 2004 Answer Key Make sure you show your work whenever a calculation is required in the space provided. Failure to do this will result in zero points being awarded. 1. What is the total number of orbitals in the entire fourth shell? 16 . (02 pts) In the fourth shell there are four subshells: the s, the p, the d, and the f. The total number of orbitals would be one from the s, three from the p, five from the d, and 7 from the f for a grand total of 16 orbitals. 2. What is the maximum number of electrons you can fit in the 6f subshell? 14 . (02 pts) This depends on how many orbitals we have there. As in any f subshell, we have 7 orbitals. Therefore, we can fit a maximum of 14 electrons. 3. What are the possible values for x in the following: (5, x , -3)? 3 and 4 . (02 pts) In theory, the possible values of x would be 0, 1, 2, 3, or 4. However, since the third quantum number is –3, that discards immediately the 0, the 1, and the 2. Therefore, the answer is 3, and 4. 4. Circle the photon with the highest energy and draw a square around the one with the longest wavelength . (04 pts) Orange Microwave Blue Yellow 5. How many electrons in the entire fourth shell could have the magnetic quantum number equal (m l ) equal to 3? 2 . (02 pts) In the entire fourth shell there are 32 possible electrons (2 × n 2 ). However, since the third quantum number is 3, that limits the possible values for the second quantum number to only l = 3. There is only one orbital that fits this description: (4, 3, 3). 6. Circle the one with the highest ionization energy. (02 pts) Al Si P S 7. Circle the one with the largest radius. (02 pts) Na Mg Al Si
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Chemistry 111 Page 2 out of 7 Exam II / Fall 2004 Answer Key 8. Determine the ground state electronic configuration for the following… (06 pts) a) 83 Bi +3 : [Xe] 6s 2 4f 14 5d 10 . b)
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F04_E2A - Chemistry 111 Page 1 out of 7 Exam II / Fall 2004...

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