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exam2key - Exam 2 BC 367 November 19, 2009 Answer Key 1. D...

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Exam 2 BC 367 November 19, 2009 Answer Key 1. D 2. D 3. B 4. A 5. A 6. A 7. B 8. E 9. B 10. D 11. a) No, the rate plots are sigmoidal. b) Inhibitor. c) The enzyme must be an allosteric enzyme with a regulatory site for ATP in addition to its substrate-binding site. 12. a) Candidate Hemoglobin Variant Solomon Normal (HbA) Jack Hb Rahere, in which Lys 82 β→ Thr Klaudia Novel Hb, with an enhanced Bohr effect Elaura Hb Johnstown, with p 50 < 5 mm Hg b) This Lys residue is involved in BPG binding. This mutant will bind BPG less readily, resulting in stabilization of the R state and shifting of the binding curve to the left. c) A mutation that leads to a new salt bridge that stabilizes the T state, such as a new His residue that binds to an Asp/Glu in another subunit. The new amino acid should have a pK a relatively close to neutrality. d) The R state is stabilized. There could be a new interaction between subunits that stabilizes the R state. e) Klaudia, because she can deliver much more O 2 at altitude than the other candidates.
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13. a) y axis has units of 1/rate (sec/nM); x axis has units of 1/[S] (nM
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exam2key - Exam 2 BC 367 November 19, 2009 Answer Key 1. D...

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