Exam 2 CH301 Mcord Sp 2009

Exam 2 CH301 Mcord Sp 2009 - Make sure you are taking the...

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Unformatted text preview: Make sure you are taking the right exam. This is Dr. McCords AFTERNOON course that is MWF from 1:00 - 2:00 PM, unique 53745. McCord MWF : 1pm NO CALCULATORS!! 1 18 1A 8A 1 2 H 2 13 14 15 16 17 He 1.008 2A 3A 4A 5A 6A 7A 4.003 3 4 5 6 7 8 9 10 Li Be B C N O F Ne 6.94 9.01 10.81 12.01 14.01 16.00 19.00 20.18 11 12 13 14 15 16 17 18 Na Mg Al Si P S Cl Ar 22.99 24.30 3B 4B 5B 6B 7B 8B 1B 2B 26.98 28.09 30.97 32.06 35.45 39.95 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr 39.10 40.08 44.96 47.90 50.94 52.00 54.94 55.85 58.93 58.71 63.55 65.41 69.72 72.64 74.92 78.96 79.90 83.80 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe 85.5 87.6 88.9 91.2 92.9 95.9 98.9 101.1 102.9 106.4 107.9 112.4 114.8 118.7 121.7 127.6 126.9 131.3 55 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn 132.9 137.3 138.9 178.5 180.9 183.9 186.2 190.2 192.2 195.1 197.0 200.6 204.4 207.2 209.0 210.0 210.0 222.0 87 88 89 104 105 106 107 108 109 110 Fr Ra Ac Rf Db Sg Bh Hs Mt Ds (223) (226) (227) (261) (262) (266) (262) (277) (268) ( ) 58 59 60 61 62 63 64 65 66 67 68 69 70 71 Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu 140.1 141.0 144.2 145.0 150.3 152.0 157.2 158.9 162.5 164.9 167.3 168.9 173.0 175.0 90 91 92 93 94 95 96 97 98 99 100 101 102 103 Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr 232.0 231.0 238.0 (237) (244) (243) (247) (247) (251) (252) (257) (258) (259) (260) Version 288 Exam 2 McCord (53745) 2 This print-out should have 26 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points In the Lewis dot structure of the molecule ClF 3 , how many unbonded electron pairs are found around the central atom? 1. 3 2. 4 3. 4. 2 correct 5. 1 Explanation: Draw the Lewis dot structure. ClF 3 has 3 Cl F single bonds and 2 lone pairs on Cl. 002 10.0 points In constructing the Lewis dot formula for CCl 3 where carbon is the central atom, give the quantities for N (needed electrons), A (available electrons) and S (shared electrons). 1. N = 32, A = 26, S = 6 correct 2. N = 32, A = 24, S = 8 3. N = 32, A = 25, S = 8 4. N = 32, A = 24, S = 6 5. N = 32, A = 26, S = 8 6. N = 32, A = 25, S = 6 Explanation: N = 8(4) = 32 A = 1 + 4 + 3(7) = 26 S = 32- 26 = 6 003 10.0 points A molecule has an angular molecular geom- etry. The hybridization on the central atom must be 1. sp 2 or sp 3 . correct 2. sp . 3. sp 3 d . 4. sp 3 or sp 3 d . 5. sp 3 . 6. sp 2 or sp 3 or sp 3 d . 7. sp or sp 2 . 8. sp 2 . Explanation: Angular molecular geometry is only possi- ble for tetrahedral and trigonal planar elec- tronic geometries which are sp 3 or sp 2 hy- bridized, respectively....
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Exam 2 CH301 Mcord Sp 2009 - Make sure you are taking the...

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