Chem302_Laude_Exam3_Spring09

Chem302_Laude_Exam3_Spring09 - Version 088 Exam 3 Laude...

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Version 088 – Exam 3 – Laude – (52390) 1 This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. - d [A] a dt = k [A] = [A] 0 - akt t 1 / 2 = [A] 0 2 ak - d [A] a dt = k [A] ln[A] = ln [A] 0 - akt t 1 / 2 = ln 2 ak - d [A] a dt = k [A] 2 1 [A] = 1 [A] 0 + akt t 1 / 2 = 1 ak [A] 0 ln a b = ln a - ln b rate = k [A] x [B] y = - 1 a × d [ A ] dt k = A exp p - E a RT P ln k 2 k 1 = E a R p 1 T 1 - 1 T 2 P 001 6.0 points Which oF the Following is not a way to fx nitrogen? 1. Use the Haber process to manuFacture NH 3 . 2. Rely on atmospheric reactions caused by lightning. 3. Rely on soil bacteria. 4. Pass nitrogen compounds over/through a catalytic converter. correct Explanation: A catalytic converter actually takes fxed oxidized nitrogen species and reduces them to to N 2 . 002 6.0 points Consider the elementary reaction: BaCO 3 ( aq ) -→ CO 2 ( aq ) + BaO( s ) IF k = 2 . 85 × 10 2 M · s 1 , and there is initially 1 M BaCO 3 , what is the halF-liFe oF the reaction? 1. 1 . 8 ms correct 2. 2 . 4 ms 3. 3 . 5 ms 4. not enough inFormation Explanation: t 1 / 2 = [BaCO 3 ] 2 · k = 1 2 · 2 . 85 × 10 2 = 1 . 8 ms 003 6.0 points What are the products oF the Hall process? 1. CO 2 2. Al 2 O 3 3. Al 2 O 3 and CO 2 4. Al and CO 2 correct Explanation: Oxidation oF the carbon anode in the smelt- ing process produces a steady amount oF CO 2 . Alumina is reduced to aluminum at the cath- ode. Side reactions oF the molten cryolite produce H±. 004 6.0 points What is the name oF the Following molecule?
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2 H 3 C CH 3 OH CH 3 1. 2-methyl-3-hexanol 2. 2-methyl-3-pentanone 3. 2-methyl-3-pentanal 4. 1,2 dimethyl-2-butanol 5. 2-methyl-3-pentanol correct Explanation: Because the hydroxyl group is centered along the longest carbon chain, we begin num- bering such that the next functional group has the lowest number, in this case 2-methyl. 005 6.0 points What is the activation energy for the for- ward reaction in the diagram below? R T P 0 10 20 30 40 E (kJ · mol 1 ) Reaction Coordinate 1. 12 . 5 kJ · mol 1 2. 17 . 5 kJ · mol 1 correct 3. 37 . 5 kJ · mol 1 4. 25 . 0 kJ · mol 1 5. 20 . 0 kJ · mol 1 6. 5 . 0 kJ · mol 1 Explanation: The diFerence in energies between the tran- sition state and the ground state reactants is 17 . 5 kJ · mol 1 . 006 6.0 points ±or a certain 3 rd order reaction, k = 2 . 35 × 10 4 M x · s y . What would be the values of x and y, respectively? 1. -3, -1 2. -2, -1 correct 3. 2, 1 4. 1, -3 5. -1, -2 6. 3, -1 Explanation: Units of M 2 · s 1 would correspond to a 3 rd order reaction. 007
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This note was uploaded on 02/09/2010 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas at Austin.

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Chem302_Laude_Exam3_Spring09 - Version 088 Exam 3 Laude...

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