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Chemistry 1A, Spring 2009
KEY
Midterm 2, Version
March 9, 2009
(90 min, closed book)
Name:___________________
SID:_____________________
TA Name:________________
•
There are 20 Multiple choice questions worth 2.5 points each.
•
There are 3, multipart, short answer questions.
•
For the multiple choice section, fill in the Scantron form AND circle your answer
on the exam.
•
Put your written answers in the boxes provided.
Full credit cannot be gained for
answers outside the boxes provided.
•
The lecture, homework, chemquizzes, discussion or experiment that each question
is based upon is listed after the question e.g. [L3, HW 1.13, CQ 7.3]
•
Unless it is specified otherwise, reduce formal charge when drawing structures
Question
Points
Score
Multiple Choice Section
50
Question 21
19
Question 22
18
Question 23
13
Total
100
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Page 2 of 10
Thermodynamics:
∆
G
°
=
∆
H
°

T
∆
S
°
∆
H
°
=
Σ
∆
H
°
f
(products)

Σ
∆
H
°
f
(reactants)
∆
S
°
=
Σ
S
°
(products)

Σ
S
°
(reactants)
∆
G
°
=
Σ
∆
G
°
f
(products)

Σ
∆
G
°
f
(reactants)
S = k
B
lnW
∆
S = q
rev
/T
∆
E = q + w
w =

P
ext
∆
V
for aA + bB
cC + dD
b
a
d
c
B
A
D
C
Q
]
[
]
[
]
[
]
[
=
At equilibrium, Q = K
∆
G =
∆
G
°
+
RTln Q
G = G° + RTln(a); a = activity =
γ
P/P° or
γ
[A]/[A]°
∆
G
°
=

RTln K
∆
G
°
=

nF
∆
Є
º
∆
Є
=
∆
Є
º  (RT/nF) lnQ
R
S
T
R
H
K
°
∆
+
°
∆
−
=
1
ln
∆
T = ik
b,f
m
Π
= iMRT
P
total
=
P
A
+ P
B
= X
A
P
A
° + X
B
P
B
°
Acid Base:
pH =  log[H
3
O
+
]
pX =

log X
]
[
]
[
log
HA
A
pK
pH
a
−
+
=
Kinetics:
[A]
t
= [A]
0
e
kt
ln[A]
t
= ln[A]
0
– kt
t
1/2
= ln2/k
1/[A]
t
= 1/[A]
0
+ kt
k = A e
(Ea/RT)
ln(k
1
/k
2
) = E
a
/R ( 1/T
2
– 1/T
1
)
t
1/2
= 1/[A]
0
k
t
1/2
= [A]
0
/kt
Quantum:
E = h
ν
λν
= c
λ
deBroglie
= h / p = h / mv
E
kin
(e) = h
ν

Φ
= h
ν
 h
ν
0
∞
−
=
R
n
Z
E
n
2
2
∆
x
∆
p ~ h
p = mv
Particle in a box (1D Quantum):
E
n
= h
2
n
2
/8mL
2
; n = 1, 2, 3...
Vibrational:
E
v
= (v + ½) hA/2
π
; A =(k/m)
½
Rotational:
E
n
= n(n + 1) hB; B = h/8
π
2
I; I = 2mr
2
m = m
A
m
B
/(m
A
+ m
B
)
Ideal Gas:
PV = nRT
RT
E
kin
2
3
=
M
3RT
v
rms
=
Constants:
N
0
= 6.02214 x 10
23
mol
1
R
∞
= 2.179874 x 10
18
J
R
∞
= 3.28984 x 10
15
Hz
k = 1.38066 x 10
23
J K
1
h = 6.62608 x 10
34
J s
m
e
= 9.101939 x 10
31
kg
c = 2.99792 x 10
8
m s
1
T (K) = T (C) + 273.15
F = 96,485 C / mol
1 V = 1 J / C
Gas Constant:
R = 8.31451 J K
1
mol
1
R = 8.20578 x 10
2
L atm K
1
mol
1
1 nm = 10
9
m
1 kJ = 1000 J
1 atm = 760 mm Hg = 760 torr
≈
1 bar
1 L atm
≈
100 J