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HW 8 Prob 3_25 extra-1 - PROBLEM 3.25 The ramp ABCD is...

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Unformatted text preview: PROBLEM 3.25 The ramp ABCD is supported by cables at corners C and D. The tension in each of the cables is 810 N. Determine the moment about A of the force exerted by (a) the cable at D, (Z7) the cable at C. SOLUTION (a) We have M A = rm >< TDE Where rE/A = (2.3 m) j TDE = lDETDE = (0.6 m)i + (3.3 m)j — (3 m)k J(0.6)2 + (3.3)2 + (3)2m = (108lN)i + (594 N) j — (540 N)k i . j k M A = 0 2.3 0 N - m 108 594 —540 = —(1242 N - m)i — (248.4 N - m)k (810 N) or MA =—(1242N-m)i—(248N-m)k 4 (b) We have M A = rG/A >< TCG 7 where rGM = (2.7 m)i + (2.3 m) j TCG_= ACGT CG _ —(.6 m)i + (3.3 m)j — (3 m)k {/(.6)2 + (3.3)2 + (3)2m = —(108 N)i + (594 N)j — (540 N)k (810N) ., 1 _] k MA: 2.7. 2.3 0 N-m —108 594 —540 = —(1242 N - m)i + (1458 N - m)j + (1852 N . m)k - or MA =—(1242N-m)i+(1458 N.m)j+(1852N’m)k 4 ...
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