SolSec 5.6 - 5 63 Problems and Solutions Section 5.6(5.67...

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5- 63 Problems and Solutions Section 5.6 (5.67 through 5.73) 5.67 Compare the resonant amplitude at steady state (assume a driving frequency of 100 Hz) of a piece of nitrite rubber at 50 ° F versus the value at 75 ° F. Use the values for η from Table 1. Solution: From Eq. (5.63), X F k j m = + ( ) 0 2 1 η ω At resonance m k = ω so X F k j F k j = ( ) = 0 0 1 1 η η The magnitude is X F k = 1 0 η At 50 ° , η = 0.5 and at 75 ° , η = 0.28, so k F X k F X 0 75 0 50 57 . 3 2 = = o o
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