5- 63
Problems and Solutions Section 5.6 (5.67 through 5.73)
5.67
Compare the resonant amplitude at steady state (assume a driving frequency of 100 Hz)
of a piece of nitrite rubber at 50
°
F versus the value at 75
°
F.
Use the values for
η
from
Table 1.
Solution:
From Eq. (5.63),
X
F
k
j
m
=
+
(
)
−
0
2
1
η
ω
At resonance
m
k
=
ω
so
X
F
k
j
F
k j
=
−
(
)
−
=
0
0
1
1
η
η
The magnitude is
X
F
k
=
1
0
η
At 50
°
,
η
= 0.5 and at 75
°
,
η
= 0.28, so
k
F
X
k
F
X
0
75
0
50
57
.
3
2
=
=
o
o

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